If a binomial distribution applies with a sample size of n = 20, find the values below. The probability of 5 successes if the probability of a success is 0.25 The probability of at least 7 successes if the probability of a success is 0.10 The expected value, n= 20, p= 0.40 d. a. b. С. The standard deviation, n= 20, p = 0.40 a. The probability of 5 successes if the probability of a success is 0.25 is (Round to four decimal places as needed.) b. The probability of at least 7 successes if the probability of a success is 0.10 is (Round to four decimal places as needed.) c. The expected value is (Type an integer or a decimal.) d. The standard deviation is (Round to four decimal places as needed.)

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A: From the provided information, P(A) = 0.36, P(A and B) = 0.32, P(A or B) = 0.50

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Q: Given P(A) = 0.27, P(A and B) = 0.33, P(A or B) = 0.41, what is P(B)? Answer in decimal form.…

A: Formula : P(A or B) = P(A) + P(B) - P(A and B)

Q: can you anatate it for me

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Q: Find P- hat and q - hat n = 76 and X = 28 Round your answer to three decimal places.

A: Answer: From the given data, Sample size(n) = 76 X = 28

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A: 5/9 = 0.55555...

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A: The probability of union of two sets are given as, P(A or B) = P(A) + P(B) – P(A and B).

Q: P(B) = 0.4 / 0.6 = 2 / 3 = 0.6667  where did all the numbers in this line come from?

A: It is given that P(A U B) = 0.8, P(Ac) = 0.6