If a ball is thrown into the air at 96 feet per second from the top of a 109-foot-tall building, its height can be modeled by the function S= 109 +96t-16, where S is in feet and t is in seconds. Complete parts a through c below. AS 300 AS 300 300- 300- 0 b. Find the height of the ball 2 seconds after it is thrown and 4 seconds after it is thrown, How can these values be equal? ft. The height of the ball 2 seconds after it is thrown is The height of the ball 4 seconds after it is thrown is ft. How can these values be equal? O A. These two values are equal because the ball was always rising between the two instances. O B. These two values are equal because the ball was always falling between the two instances. O D. These two values are equal because the ball was rising to a maximum height at the first instance and then after reaching the maximum height, the ball was falling at the second instance. In the first instance, 2 seconds after throwing the ball in an upward direction, it will reach the height 237 ft and in the second instance, 4 seconds after the ball is thrown, again it will come back to the height 237 f. Next O C. These two values are equal because the ball was falling to a minimum height at the first instance and then it was started to rising at the second instance.

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