If A = B = [2 51 L6 [3 В 15 then show that -41 [4] (i) (AB)-1 = B-'A-1 (ii) (AB)T = B" AT (ii) (ЗА — 2B) — 3АТ - 2ВТ (iii) det(AB) = det A· det B %3D |
If A = B = [2 51 L6 [3 В 15 then show that -41 [4] (i) (AB)-1 = B-'A-1 (ii) (AB)T = B" AT (ii) (ЗА — 2B) — 3АТ - 2ВТ (iii) det(AB) = det A· det B %3D |
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.
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9ii- I want solution of this question sub-parts with all steps, please. Thanks
![ii.
If A =
51
% D
L6 8
=: , then show that
[4]
(i)
(AB)-1 = B-1A-1
(ii) (AB)" = B"AT
(ii)
(ЗА — 2B)Т — 3АТ - 2BТ
(iii) det(AB) = det A· det B](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F77e6d6f6-5f7b-4849-9603-81aa5dc8f296%2F624426cf-2f0e-438b-b33a-243cab696fc5%2Fnrh22am_processed.jpeg&w=3840&q=75)
Transcribed Image Text:ii.
If A =
51
% D
L6 8
=: , then show that
[4]
(i)
(AB)-1 = B-1A-1
(ii) (AB)" = B"AT
(ii)
(ЗА — 2B)Т — 3АТ - 2BТ
(iii) det(AB) = det A· det B
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