If a 35.9%-efficient Carnot heat engine (left figure) is run in reverse so as to form a refrigerator (right figure), what would be this refrigerator's coefficient of performance? Energy IQ enters the engine. Energy IQ leaves the engine. The engine does work Weng Hot reservoir at Th Pr Heat engine Le Cold reservoir at T Weng Q Energy IQ is expelled to the hot reservoir. Energy IQ is drawn from the cold reservoir. Work Wis done on the heat pump. Hot reservoir at Th 2h Heat pump Q₂ Cold reservoir at T W
If a 35.9%-efficient Carnot heat engine (left figure) is run in reverse so as to form a refrigerator (right figure), what would be this refrigerator's coefficient of performance? Energy IQ enters the engine. Energy IQ leaves the engine. The engine does work Weng Hot reservoir at Th Pr Heat engine Le Cold reservoir at T Weng Q Energy IQ is expelled to the hot reservoir. Energy IQ is drawn from the cold reservoir. Work Wis done on the heat pump. Hot reservoir at Th 2h Heat pump Q₂ Cold reservoir at T W
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Expert Solution
Step 1
Given that the efficiency of heat engine is efficiency=35.9%= 35.9/100=0.359
Coefficient of performance of refridgerator is given by
K=[1/(efficiency of heat engine)]-1
K=[1/(0.359)]-1
K=1.785
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