if a < - 1 2x – 1 if -1 < « < 2 if a > 2 -3 Sketch a graph of f(x) 4 5 4 -3 -2 -1 -1 2 3 4 -2 %24 2.

Question
The image provides instructions to sketch a graph of the piecewise function \( f(x) \), defined as follows:
\[ 
f(x) = \begin{cases} 
-3 & \text{if } x \leq -1 \\
2x - 1 & \text{if } -1 < x \leq 2 \\
2 & \text{if } x > 2 
\end{cases}
\]

Additionally, the image includes a coordinate plane (graph grid) with the x-axis and y-axis both labeled from -5 to 5. The grid appears blank with no features or plots. 

Here is a detailed explanation of how to sketch the graph of the function \( f(x) \):

1. For \( x \leq -1 \):
   - The function \( f(x) = -3 \) is a horizontal line since the output value is always -3 regardless of the input. 
   - Plot a horizontal line at \( y = -3 \) for all \( x \leq -1 \).

2. For \( -1 < x \leq 2 \):
   - The function \( f(x) = 2x - 1 \) is a linear function with a slope of 2 and a y-intercept of -1.
   - For \( x = -1 \): \( f(-1) = 2(-1) - 1 = -2 - 1 = -3 \).
     - Since this point overlaps with the value at \( x = -1 \) from the previous piece, it should be a continuation.
   - For \( x = 2 \): \( f(2) = 2(2) - 1 = 4 - 1 = 3 \). Mark an open circle at \( (2, 3) \) because this value is exclusive for this piece.
   - Plot a dashed (indicating it is cut off at the boundaries) line connecting these calculated points (\( (-1, -3) \) to \( (2, 3) \)).

3. For \( x > 2 \):
   - The function \( f(x) = 2 \) is constant.
   - Plot a horizontal line at \( y = 2 \) for all \( x > 2 \). Start with an open circle at \( (2, 3) \) to show continuity
Transcribed Image Text:The image provides instructions to sketch a graph of the piecewise function \( f(x) \), defined as follows: \[ f(x) = \begin{cases} -3 & \text{if } x \leq -1 \\ 2x - 1 & \text{if } -1 < x \leq 2 \\ 2 & \text{if } x > 2 \end{cases} \] Additionally, the image includes a coordinate plane (graph grid) with the x-axis and y-axis both labeled from -5 to 5. The grid appears blank with no features or plots. Here is a detailed explanation of how to sketch the graph of the function \( f(x) \): 1. For \( x \leq -1 \): - The function \( f(x) = -3 \) is a horizontal line since the output value is always -3 regardless of the input. - Plot a horizontal line at \( y = -3 \) for all \( x \leq -1 \). 2. For \( -1 < x \leq 2 \): - The function \( f(x) = 2x - 1 \) is a linear function with a slope of 2 and a y-intercept of -1. - For \( x = -1 \): \( f(-1) = 2(-1) - 1 = -2 - 1 = -3 \). - Since this point overlaps with the value at \( x = -1 \) from the previous piece, it should be a continuation. - For \( x = 2 \): \( f(2) = 2(2) - 1 = 4 - 1 = 3 \). Mark an open circle at \( (2, 3) \) because this value is exclusive for this piece. - Plot a dashed (indicating it is cut off at the boundaries) line connecting these calculated points (\( (-1, -3) \) to \( (2, 3) \)). 3. For \( x > 2 \): - The function \( f(x) = 2 \) is constant. - Plot a horizontal line at \( y = 2 \) for all \( x > 2 \). Start with an open circle at \( (2, 3) \) to show continuity
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