If a 1,000-kg car is traveling at 20.0 m/s when it reaches the bottom of a circular hill of radius 8.00 m, what normal force does the road exert on the car at the bottom of the hill? a. 59,800 N b. 82,500 N C. 40,000 N d. 70,000 N e. 19,600 N

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### Question 3

If a 1,000-kg car is traveling at 20.0 m/s when it reaches the bottom of a circular hill of radius 8.00 m, what normal force does the road exert on the car at the bottom of the hill?

- a. 59,800 N
- b. 82,500 N
- c. 40,000 N
- d. 70,000 N
- e. 19,600 N
Transcribed Image Text:### Question 3 If a 1,000-kg car is traveling at 20.0 m/s when it reaches the bottom of a circular hill of radius 8.00 m, what normal force does the road exert on the car at the bottom of the hill? - a. 59,800 N - b. 82,500 N - c. 40,000 N - d. 70,000 N - e. 19,600 N
Expert Solution
Step 1

Given:-

Mass of the car is m=1000 kg.

Speed of the car at the bottom of the hill is v=20.0 m/s.

Radius of the circular hill is r=8.00 m.

 

Free-body diagram:-

Physics homework question answer, step 1, image 1

In the diagram N is the normal force on the car, Fc is the centripetal force and W is the weight of the car.

From the diagram we can write normal force on the car at the bottom of the hill is 

N=Fc+W

N=mv2r+mg

N=mv2r+g..............(1)

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