If a 0.019 C charge is moving perpendicular to a 0.9 T magnetic field at 465 m/s, find the force on the charged particle. If a 7.7 A current runs in a 2.5 meter long wire in a perpendicular magnetic field of 2.4 T. Find the force on the wire. Find the force per length (F/L) between two long parallel wires, if they are 0.84 m apart and 11 = 44 A and 12 = 97 A.
If a 0.019 C charge is moving perpendicular to a 0.9 T magnetic field at 465 m/s, find the force on the charged particle. If a 7.7 A current runs in a 2.5 meter long wire in a perpendicular magnetic field of 2.4 T. Find the force on the wire. Find the force per length (F/L) between two long parallel wires, if they are 0.84 m apart and 11 = 44 A and 12 = 97 A.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Please need help on three part question of magnetic force thank you.
![If a 0.019 C charge is moving perpendicular to a 0.9 T magnetic field at 465 m/s, find
the force on the charged particle.
If a 7.7 A current runs in a 2.5 meter long wire in a perpendicular magnetic field of
2.4 T. Find the force on the wire.
Find the force per length (F/L) between two long parallel wires, if they are 0.84 m
apart and 11 44 A and 12 = 97 A.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbbba0909-7b4f-4e80-8e24-06dfda2d061e%2F538b37dc-dd34-401a-aae8-d363b71fedd3%2Fn6u2n8r_processed.jpeg&w=3840&q=75)
Transcribed Image Text:If a 0.019 C charge is moving perpendicular to a 0.9 T magnetic field at 465 m/s, find
the force on the charged particle.
If a 7.7 A current runs in a 2.5 meter long wire in a perpendicular magnetic field of
2.4 T. Find the force on the wire.
Find the force per length (F/L) between two long parallel wires, if they are 0.84 m
apart and 11 44 A and 12 = 97 A.
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