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If 94.92 mL of a solution of HCl are equivalent to 43.76 mL of a solution of NaOH and if 49.14 mL of the latter will neutralize 0.2162 g of KHC2O4 · H2C2O4 • H2O. What volume of water should be added to a liter of the acid in order to make it 0.5050 normal?

If 94.92 mL of a solution of HCl are equivalent to 43.76 mL of a solution of NaOH and if 49.14 mL of the latter will neutralize 0.2162 g of KHC2O4 · H2C2O4 • H2O. What volume of water should be added to a liter of the acid in order to make it 0.5050 normal?

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter4: Chemical Reactions In Solution
Section: Chapter Questions
Problem 4.90QE: What is the molar concentration of an H2SO4 solution if a 50.0-mL sample requires 9.65 mL of a 1.33...
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If 94.92 mL of a solution of HCl are equivalent to 43.76 mL of a solution of NaOH and if 49.14 mL of the latter will neutralize 0.2162 g of KHC204 · H2C2O4 • H2O. What volume of water should be added to a liter of the acid in order to make it 0.5050 normal?
Transcribed Image Text:If 94.92 mL of a solution of HCl are equivalent to 43.76 mL of a solution of NaOH and if 49.14 mL of the latter will neutralize 0.2162 g of KHC204 · H2C2O4 • H2O. What volume of water should be added to a liter of the acid in order to make it 0.5050 normal?
Normality of NaOH * 0.0519 0.0692 0.0173 0.0346 Volume of water * 15 mL 10 mL 345 mL 674 mL
Transcribed Image Text:Normality of NaOH * 0.0519 0.0692 0.0173 0.0346 Volume of water * 15 mL 10 mL 345 mL 674 mL
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