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If 75mL of 5.5M solution of NAOH (39.997 g/mol) was required to consume all the molar equivalents of copper (II) nitrate (187.56 g/mol), determine the grams of copper (II) hydroxide (97.561g/mol) produced. Cu(NO;)2 + 2NaOH → Cu(OH)2 + 2NANO3 Group of answer choices 30 g 10 g 0g 50 g 20 g 40 g

If 75mL of 5.5M solution of NAOH (39.997 g/mol) was required to consume all the molar equivalents of copper (II) nitrate (187.56 g/mol), determine the grams of copper (II) hydroxide (97.561g/mol) produced. Cu(NO;)2 + 2NaOH → Cu(OH)2 + 2NANO3 Group of answer choices 30 g 10 g 0g 50 g 20 g 40 g

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Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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W Select Adobe PDF Paragraph Styles Editing Adobe Acro If 75mL of 5.5M solution of NaOH (39.997 g/mol) was required to consume all the molar equivalents of copper (II) nitrate (187.56 g/mol), determine the grams of copper (II) hydroxide (97.561g/mol) produced. Cu(NO3)2 + 2NAOH → Cu(OH)2 + 2NANO3 Group of answer choices 30 g 10 g 0 g 50 g 20 g 40 g a States) 96% 画 Home End Insert F5 F6 F7 F8 F9 F10 F11 F12 & 6 7 8 9. T Y U + II
Transcribed Image Text:W Select Adobe PDF Paragraph Styles Editing Adobe Acro If 75mL of 5.5M solution of NaOH (39.997 g/mol) was required to consume all the molar equivalents of copper (II) nitrate (187.56 g/mol), determine the grams of copper (II) hydroxide (97.561g/mol) produced. Cu(NO3)2 + 2NAOH → Cu(OH)2 + 2NANO3 Group of answer choices 30 g 10 g 0 g 50 g 20 g 40 g a States) 96% 画 Home End Insert F5 F6 F7 F8 F9 F10 F11 F12 & 6 7 8 9. T Y U + II
Expert Solution
Basic

Cu(NO3)2 + 2NaOH → Cu(OH)2 + 2NaNO3

From this Balanced chemical equation we get that ;

2 mol NaOH Produce = 1 mol Cu(OH)2 

 

* NaOH

Volume = 75 mL = 0.075 L

Molarity = 5.5 M = 5.5 mol/L

Molar mass = 39.997 g/mol

 

* Moles of NaOH

= Molarity × volume

= 5.5 mol/L × 0.075 L

= 0.412 mol

Moles of NaOH = 0.412 mol

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