If 75mL of 5.5M solution of NAOH (39.997 g/mol) was required to consume all the molar equivalents of copper (II) nitrate (187.56 g/mol), determine the grams of copper (II) hydroxide (97.561g/mol) produced. Cu(NO;)2 + 2NaOH → Cu(OH)2 + 2NANO3 Group of answer choices 30 g 10 g 0g 50 g 20 g 40 g
If 75mL of 5.5M solution of NAOH (39.997 g/mol) was required to consume all the molar equivalents of copper (II) nitrate (187.56 g/mol), determine the grams of copper (II) hydroxide (97.561g/mol) produced. Cu(NO;)2 + 2NaOH → Cu(OH)2 + 2NANO3 Group of answer choices 30 g 10 g 0g 50 g 20 g 40 g
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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If 75mL of 5.5M solution of NaOH (39.997 g/mol) was required to consume all the molar
equivalents of copper (II) nitrate (187.56 g/mol), determine the grams of copper (II) hydroxide
(97.561g/mol) produced.
Cu(NO3)2 + 2NAOH → Cu(OH)2 + 2NANO3
Group of answer choices
30 g
10 g
0 g
50 g
20 g
40 g
a States)
96%
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If 75mL of 5.5M solution of NaOH (39.997 g/mol) was required to consume all the molar
equivalents of copper (II) nitrate (187.56 g/mol), determine the grams of copper (II) hydroxide
(97.561g/mol) produced.
Cu(NO3)2 + 2NAOH → Cu(OH)2 + 2NANO3
Group of answer choices
30 g
10 g
0 g
50 g
20 g
40 g
a States)
96%
画
Home
End
Insert
F5
F6
F7
F8
F9
F10
F11
F12
&
6
7
8
9.
T
Y
U
+ II
Expert Solution
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Basic
Cu(NO3)2 + 2NaOH → Cu(OH)2 + 2NaNO3
From this Balanced chemical equation we get that ;
2 mol NaOH Produce = 1 mol Cu(OH)2
* NaOH
Volume = 75 mL = 0.075 L
Molarity = 5.5 M = 5.5 mol/L
Molar mass = 39.997 g/mol
* Moles of NaOH
= Molarity × volume
= 5.5 mol/L × 0.075 L
= 0.412 mol
Moles of NaOH = 0.412 mol
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