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If 65.0 kg of ammonia and 80.0 kg of oxygen are fed to a batch reactor, determine the limiting reactant, the amount in moles by which the other reactant is in excess, and the extent of the reaction (molar) and the mass of NO produced (kg) if the reaction proceeds to completion. First find the number of moles that corresponds to 65.0 kg of ammonia (NH3). i kmol NH3 Now find the number of moles that corresponds to 80.0 kg of O2. i kmol O2

If 65.0 kg of ammonia and 80.0 kg of oxygen are fed to a batch reactor, determine the limiting reactant, the amount in moles by which the other reactant is in excess, and the extent of the reaction (molar) and the mass of NO produced (kg) if the reaction proceeds to completion. First find the number of moles that corresponds to 65.0 kg of ammonia (NH3). i kmol NH3 Now find the number of moles that corresponds to 80.0 kg of O2. i kmol O2

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Use the extent of reaction e method and complete solution.
If 65.0 kg of ammonia and 80.0 kg of oxygen are fed to a batch reactor, determine the limiting reactant, the amount in moles by which the other reactant is in excess, and the extent of the reaction (molar) and the mass of NO produced (kg) if the reaction proceeds to completion. First find the number of moles that corresponds to 65.0 kg of ammonia (NH3). i kmol NH3 Now find the number of moles that corresponds to 80.0 kg of O2. i kmol O2
Transcribed Image Text:If 65.0 kg of ammonia and 80.0 kg of oxygen are fed to a batch reactor, determine the limiting reactant, the amount in moles by which the other reactant is in excess, and the extent of the reaction (molar) and the mass of NO produced (kg) if the reaction proceeds to completion. First find the number of moles that corresponds to 65.0 kg of ammonia (NH3). i kmol NH3 Now find the number of moles that corresponds to 80.0 kg of O2. i kmol O2
Ammonia is oxidized to form nitric oxide in the following reaction: 4NH3+ 502 –→4NO+ 6H2O
Transcribed Image Text:Ammonia is oxidized to form nitric oxide in the following reaction: 4NH3+ 502 –→4NO+ 6H2O
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