If 500 J of work are required to carry a charged particle between two points with a potential difference of 20V, the magnitude of the charge on the particle is: a.12.50 b. 0.040C c. cannot be computed unless the path is given d. 200
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A: Potential difference between plate = V = 600v distance between plate = d = 4.5 mm = 4.5×10-3m
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A: Work done W = 2.05 × 10-3J Potential difference VA- VB = 40.9 V
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- Suppose an electron is released from rest in a uniform electric field whose magnitude is 6.30 x 10³ V/m. (a) Through what potential difference will it have passed after moving 1.00 cm? 2.21*10**-53 X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. V (b) How fast will the electron be moving after it has traveled 1.00 cm? m/sParticle A has a charge of 10uC and a mass of 0.001kg. Particle A starts out at a speed of v = 1000m/s. At some time later, particle A has come to rest. What is the electric potential difference AV from where particle A started to where it stopped? Ignore gravity.A proton (mass = 1.67 × 10-27 kg, charge = 1.60 × 10-19 C) moves from point A to point B under the influence of an electrostatic force only. At point A the proton moves with a speed of 50 km/s. At point B the speed of the proton is 92.9 km/s. Determine the potential difference VB -VA (in units of А volts). Select one: O A. 24.02 О в. 31.38 Ос. -50.38 O D. -31.99 O E. 2.12