If 4-inch (100 mm) Schedule 40 sprinkler piping has an actual inside diameter of 4.026 inches (102.3 mm), how many gallons (liters) of water could be contained in 135 feet (40 meters) of this pipe? How much would the water in this pipe weigh? US unites ( answer by pounds )
Unitary Method
The word “unitary” comes from the word “unit”, which means a single and complete entity. In this method, we find the value of a unit product from the given number of products, and then we solve for the other number of products.
Speed, Time, and Distance
Imagine you and 3 of your friends are planning to go to the playground at 6 in the evening. Your house is one mile away from the playground and one of your friends named Jim must start at 5 pm to reach the playground by walk. The other two friends are 3 miles away.
Profit and Loss
The amount earned or lost on the sale of one or more items is referred to as the profit or loss on that item.
Units and Measurements
Measurements and comparisons are the foundation of science and engineering. We, therefore, need rules that tell us how things are measured and compared. For these measurements and comparisons, we perform certain experiments, and we will need the experiments to set up the devices.
If 4-inch (100 mm) Schedule 40 sprinkler piping has an actual inside diameter of 4.026 inches (102.3 mm), how many gallons (liters) of water could be contained in 135 feet (40 meters) of this pipe? How much would the water in this pipe weigh?
US unites ( answer by pounds )
step:-1
Volume of pipe =
Here, r denotes inside radius and h denotes height.
Given that inside radius of pipe = 4.026 inches = 0.3355 feet
height pf pipe = 135 feet
volume of pipe =
Note:- radius =
volume of pipe = 11.9346 cubic feet
step:-2
1 cubic foot =7.48 gallon of water then
47.7385 cubic feet = of water
1 gallon of water = 8.34 lbs (pound)
89.2710 gallon = 89.2710 8.34 =744.5201 lbs
Step by step
Solved in 2 steps
