If 3.05 mol of an ideal gas has a pressure of 2.58 atm and a volume of 66.37 L, what is the temperature of the sample in degrees Celsius? T = °C

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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**Problem Statement:**

If 3.05 mol of an ideal gas has a pressure of 2.58 atm and a volume of 66.37 L, what is the temperature of the sample in degrees Celsius?

\[ T = \underline{\hspace{70mm}} \, ^\circ\text{C} \]

**Instructions:**

Use the ideal gas law to calculate the temperature:
\[ PV = nRT \]

Where:
- \( P \) is the pressure in atmospheres (atm).
- \( V \) is the volume in liters (L).
- \( n \) is the amount of substance in moles (mol).
- \( R \) is the ideal gas constant, \( R = 0.0821 \, \text{L} \cdot \text{atm} / \text{mol} \cdot \text{K} \).
- \( T \) is the temperature in Kelvin (K).

To find the temperature in degrees Celsius, use the conversion:
\[ T(^\circ \text{C}) = T(\text{K}) - 273.15 \]
Transcribed Image Text:**Problem Statement:** If 3.05 mol of an ideal gas has a pressure of 2.58 atm and a volume of 66.37 L, what is the temperature of the sample in degrees Celsius? \[ T = \underline{\hspace{70mm}} \, ^\circ\text{C} \] **Instructions:** Use the ideal gas law to calculate the temperature: \[ PV = nRT \] Where: - \( P \) is the pressure in atmospheres (atm). - \( V \) is the volume in liters (L). - \( n \) is the amount of substance in moles (mol). - \( R \) is the ideal gas constant, \( R = 0.0821 \, \text{L} \cdot \text{atm} / \text{mol} \cdot \text{K} \). - \( T \) is the temperature in Kelvin (K). To find the temperature in degrees Celsius, use the conversion: \[ T(^\circ \text{C}) = T(\text{K}) - 273.15 \]
Expert Solution
Step 1

Given 

Number of mole of ideal gas ( n )  =  3.05 mole 

Pressure ( P ) = 2.58 atm 

Volume ( V )  = 66.37 Liter 

Temperature ( T ) = ? 

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