If 122 mL of allM glucose solution is diluted to 550.0 mL, what is the molarity of the diluted solution? Express your answer using two significant figures.
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- Given the following data, what is the molarity? Include the relative error Error is 1.0 mg or 1.0e-4A solution of HCl was titrated against sodium carbonate. What is the average normality of acid in the given data? (MW Na₂CO3 = 106) T2 0.3479 0.3562 0.3042 Weight (g) Initial V (ml) 0.80 1.60 35.20 36.70 39.80 Final V (mL) Vol HCl used (mL) 35.10 39.40 N of HCl (eq/L) 0.1954 0.1870 Average N of HCl (eq/L)Determine the concentrations of hydronium and hydroxide ions in 0.020637894968 M aqueous sodium hydroxide.Kw = 1.0E-14. A)Hydroxide ion concentration? B)Hydronium ion concentration?
- asia Fuqua Leam X e Home-Liferay www-awu.aleks.com = CHEMICAL REACTIONS Calculating molarity using solute mass mol/L. X F 12PM SPAN 101 Instructions Explanation Check X X A chemist prepares a solution of potassium permanganate (KMnO) by measuring out 1.5 g of potassium permanganate into a 50. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's potassium permanganate solution. Be sure your answer has the correct number of significant digits. S VHL Central Code Activation X O M + 0/5 ©2023 McGraw Hill LLC. All Rights Reserved. Terms of Use Terms of Use | Privacy Center Ala: Acce Jan 130.8 mg NaCl in 127 5 mL of solution Express the molarity in moles per liter to three significant figures • View Available Hint(s) M(NaCl) = Submit Provide Feedback F6 F7 F8 F9 F10 F11 24 A! ( asap) if you have already answerd plz do not answer ,
- Density of solution:Trial 1: 1.2 g/mLTrial 2: 1.2 g/mLTrial 3: 1.2 g/mL Average density = 1.2 g/mL What is the relative average deviaion, %?VIII. A primary standard of HCI is sodium carbonate, Na2CO3. A measured mass of solid Na2CO3, mNa2CO3' in grams, is dissolved in water and then titrated with HCI solution using methyl 2 NaCl + CO2 + H2O. orange indicator. The reaction is: Na2CO3 + 2 HCI- Complete the following formulas using the context described above: MHCI × VHCI in mL at the methyl orange endpoint = mNa2CO3 × ( )= mol of Na2CO3 mol of Na2CO3 X (— ( - - )= mol of HCl8
- View Assessment ← C Pri Ter Acc X 13 minutes remaining Question 1 blackboard.matc.edu/ultra/courses/_525703_1/outline/assessment/_1556 Blank 1 X Blank 2 Blank 3 All answers must have the correct units. Watch your significant digits! A 55.0 g sample of sugar (C12H22011) is dissolved in 170. g of water. a. What is the mass of the solute? Blank 1 g b. What is the mass of the solvent? Blank 2 g c. What is the mass of the solution? Blank 3 g d. What is the percentage by mass of this solution? (% m/m) Blank 4 % Blank 4 Add your answer Add your answer Add your answer Add your answer Courses Last saved 12:59:40 PM X Questions Filter (6) ▼ + K First < Previous NextAktiv Chemistry → C < + X b Success Confirmation of QX M Your Chemistry answer is rex b Answered: How many mL o x b Answered: A student combi x app.101edu.co Time's Up! A 0.660 M solution of KCI needs to be prepared through dilution. A 2.00 M stock solution will be added to a 0.250 L volumetric flask and then water will be added to the 0.250 L mark. Determine the volume (in mL) of the 2.00 M stock solution of KCI needed to produce this solution. 1 4 7 +/- New Tab 2 5 8 mL 3 6 9 G 0 x + Submit X C x 100Table 10.2 Samples Placed in Water (data) Sample Dialysis tubing containing sugar solution ass Before Soakin lon 5.083 Prune Mass After Soaki 5.480 12.652 11.278 Table 10.3 (report) hange in Sample as urroundin irectiono onc. of Solution (inside sample Sample lativ en Dialysis tubing + water Dialysis tubing + sugar solution Prune Sugar solution Pure water Sugar solution Pure water Prune