If 1.00 mol of argon is placed in a 0.500-L container at 26.0 °C, what is the difference between the ideal pressure (as predicted by the ideal gas law) and the real pressure (as predicted by the van der Waals equation)? For argon, a = 1.345 (L² · atm)/mol² and b = 0.03219 L/mol. Express your answer to two significant figures and include the appropriate units. ► View Available Hint(s) μᾶ ? Pideal - Preal = Value Units

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Chapter1: Chemical Foundations
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If 1.00 mol of argon is placed in a 0.500-L container at 26.0 °C, what is the difference between the ideal pressure (as
predicted by the ideal gas law) and the real pressure (as predicted by the van der Waals equation)? For argon,
a = 1.345 (L² atm)/mol² and b = 0.03219 L/mol.
Express your answer to two significant figures and include the appropriate units.
View Available Hint(s)
0
μĂ
?
Pideal - Preal
Value
Units
=
Transcribed Image Text:If 1.00 mol of argon is placed in a 0.500-L container at 26.0 °C, what is the difference between the ideal pressure (as predicted by the ideal gas law) and the real pressure (as predicted by the van der Waals equation)? For argon, a = 1.345 (L² atm)/mol² and b = 0.03219 L/mol. Express your answer to two significant figures and include the appropriate units. View Available Hint(s) 0 μĂ ? Pideal - Preal Value Units =
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