If 0.8% of the fuses delivered to an arsenal are defective, use the Poisson approximation to determine the probability that 4 fuses will be defective in a random sample of 400.
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Q: The U.S. Energy Information Administration claimed that U.S. residential customers used an average…
A: Given,sample size(n)=153sample mean(x¯)=10,586standard deviation(σ)=2509α=0.05
Q: The U.S. Energy Information Administration claimed that U.S. residential customers used an average…
A: In hypothesis testing, we start by stating the null hypothesis (H0) and the alternative hypothesis…
Q: The U.S. Energy Information Administration claimed that U.S. residential customers used an average…
A: The objective of this question is to determine whether there is sufficient evidence to support the…
Q: Use a normal approximation to find the probability of the indicated number of voters. In this case,…
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Q: Use a normal approximation to find the probability of the indicated number of voters. In this case,…
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Q: The U.S. Energy Information Administration claimed that U.S. residential customers used an average…
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Q: Use a normal approximation to find the probability of the indicated number of voters. In this case,…
A: Answer: From the given data, Selected sample size (n) = 169 P(voted) = p = 22% = 0.22 Here n is…
Q: The National Academy of Science reported that 31 % of research in mathematics is published by US…
A: p=0.31 n=188 x=74
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A: Given,n=186x=92p^=xnp^=92186=0.4946α=0.05
Q: Use a normal approximation to find the probability of the indicated number of voters. In this case,…
A: Solution
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Q: Step 2 of 3 : Compute the value of the test statistic.
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- The U.S. Energy Information Administration claimed that U.S. residential customers used an average of 10,476 kilowatt hours (kWh) of electricity this year. A local power company believes that residents in their area use more electricity on average than EIA's reported average. To test their claim, the company chooses a random sample of 153 of their customers and calculates that these customers used an average of 10,767 kWh of electricity last year. Assuming that the population standard deviation is 2478 kWh, is there sufficient evidence to support the power company's claim at the 0.05 level of significance? Step 3 of 3: Draw a conclusion and interpret the decision.The U.S. Energy Information Administration claimed that U.S. residential customers used an average of 10,069 kilowatt hours (kWh) of electricity this year. A local power company believes that residents in their area use more electricity on average than EIA's reported average. To test their claim, the company chooses a random sample of 171 of their customers and calculates that these customers used an average of 10,461 kWh of electricity last year. Assuming that the population standard deviation is 2973 kWh, is there sufficient evidence to support the power company's claim at the 0.01 level of significance? Step 3 of 3: Draw a conclusion and interpret the decision.The U.S. Energy Information Administration claimed that U.S. residential customers used an average of 10,941 kilowatt hours (kWh) of electricity this year. A local power company believes that residents in their area use more electricity on average than EIA's reported average. To test their claim, the company chooses a random sample of 115 of their customers and calculates that these customers used an average of 11,425 kWh of electricity last year. Assuming that the population standard deviation is 3217 kWh, is there sufficient evidence to support the power company's claim at the 0.02 level of significance? Step 3 of 3: Draw a conclusion and interpret the decision.
- The U.S. Energy Information Administration claimed that U.S. residential customers used an average of 10,069 kilowatt hours (kWh) of electricity this year. A local power company believes that residents in their area use more electricity on average than EIA's reported average. To test their claim, the company chooses a random sample of 171 of their customers and calculates that these customers used an average of 10,461 kWh of electricity last year. Assuming that the population standard deviation is 2973 kWh, is there sufficient evidence to support the power company's claim at the 0.01 level of significance? Step 2 of 3: Compute the value of the test statistic. Round your answer to two decimal places.For a Poisson random variable, what is the relationship between its parameter and its mean?use a normal approximation to find the probability of the indicated number of voters. in the case, assume that 136 eligible voters aged 18-24 are randomly selected. suppose a previous study showed that among eligible voters aged 18-24, 22% of them voted. probability that exactly 36 voted.
- Data from 14 cities were combined for a 20-year period, and the total 280 city-years included a total of 107 homicides. After finding the mean number of homicides per city-year, find the probability that a randomly selected city-year has the following numbers of homicides, then compare the actual results to those expected by using the Poisson probabilities:A certain type of tree has seedlings randomly dispersed in a large area, with the mean density of seedlings being approximately three per square yard. If the seedlings are randomly dispersed, the number of seedlings per region, Y can be modelled as a Poisson random variable. If a 1 forester randomly locates ten 1-square-yard sampling regions in the area, the probability that none of the regions will contain seedlings is 0.0498. 2.3.1 If the seedlings really are randomly dispersed, the number of seedlings per region, Y, can be modelled as a Poisson random variable with 2 = 3. Interpret 1 =3. 2.3.2 State the moment generating function_of the random variable Y.Use a normal approximation to find the probability of the indicated number of voters. In this case, assume that 131 eligible voters aged 18-24 are randomly selected. Suppose a previous study showed that among eligible voters aged 18-24, 22% of them voted. Probability that fewer than 32 voted
- Of a random sample of 100 college students, 35 expected to achieve a higher standard of living than their parents, 43 expected a lower standard of living, and 22 expected about the same standard of living as their parents. Do these data present strong evidence that, for the population of students, more expect a lower standard of living compared with their parents than expect a higher standard of living?Use a normal approximation to find the probability of the indicated number of voters. In this case, assume that 143 eligible voters aged 18-24 are randomly selected. Suppose a previous study showed that among eligible voters aged 18-24, 22% of them voted. Probability that exactly 33 votedThe U.S. Energy Information Administration claimed that U.S. residential customers used an average of 10,817 kilowatt hours (kWh) of electricity this year. A local power company believes that residents in their area use more electricity on average than EIA's reported average. To test their claim, the company chooses a random sample of 174 of their customers and calculates that these customers used an average of 11,156kWh of electricity last year. Assuming that the population standard deviation is 1913kWh, is there sufficient evidence to support the power company's claim at the 0.05 level of significance. Step 1 of 3 : State the null and alternative hypotheses for the test. Choose one option below H0: μ=10,817 HA: μ⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯10,817 A.≠ B.< C.> Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.
