assume that the turbine is operating at a temperature of 800 degrees Rankine PROBLEM 1Steam at 1800 Ibf/in.? and 1100°Fenters a turbine operating at steadystate. As shown in the figure, 20%of the entering mass flow isextracted at 600 Ibf/in.? and 500°F.Heat transferW.turbineThe rest of the steam exits as aP1 = 1800 lbf/in.?T = 1100°FTurbinesaturated vapor at 1 Ibf/in.? Theturbine develops a power output of6.8 X 106 Btu/h. Heat transfer fromthe turbine to the surroundingsoccurs at a rate of 5 X 10* Btu/h.13Saturated vaporP3 = 1 lbf/in.?m2 = 0.20 m,P2 = 600 lbf/in.?T2 = 500°F%3DPart a.) Neglecting kinetic andpotential energy effects, determine the mass flow rate of the steam entering the turbinein Ib/s.Part b.) Determine the entropy production (0) of this turbine.2. Equation Sheets1st LawT(K)=TCC)+273.15COPAU +AKE +APE -Q-WdKE dPE dU1-PropertiesA-u+ PCompressiblity-Q-diClosed SystemsRTPP, -2nd LawA-AC,7, -7)P.Saturated regionConstant Pressure WorkW- PV,-)dtv=v, +v, -v,)=", +xtu, -,)Polytropic WorkPolytropic processPV" - constant1-Open SystemsMassSubcooled regionT.P)= (T)=v,()CyclesDesired OutputRequired InputdmT.P) = (T)=u,T)diT.P) =u, (T)-P*v, (r)VAHeat engine (Power plant)Ideal GasP-RT1st LawPV = mRTdER-0.2870klkg Ke-1-dt2nd LawAir Conditioner and RefrigeratorCOP.W. L-1Ideal Gas isentropicdtPP.2.Isentropic efficienciesCOP(h -h)Isentropie Turbine Work (h -h)Actual Turbine WorkIsentropic Compressor Work (h, -k)Actual Compressor WorkHeat Pump(h, -4)P = PIseniropic Pump Work (P, - P)Actual Pump Work(h, -h,)Regeneration optimal flow split

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Answered: ID/S. Part b.) Determine the entropy…

Engineering

Mechanical Engineering

ID/S. Part b.) Determine the entropy production (o) of this turbine.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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