idom sample devices, tne nean repair cost was $60.00 and Standard deviation was $14.00. Assume the population normaily distributed and distribution to find the margin or error and con confidence interval for the population mean. Interpret the results. The 95% confidence interval for the population mean p is ( ). (Round to two decimal places as needed.) The margin of error is $ (Round to two decimal places as needed.) Interpret the results. Choose the correct answer below. O A. If a large sample of mobile devices are taken approximately 95% of them will have repair costs between the bounds of the confidence interval. O B. With 95% confidence, it can be said that the repair cost is between the bounds of the confidence interval. OC. It can be said that 95% of mobile devices have a repair cost between the bounds of the confidence interval. O D. With 95% confidence, it can be said that the population mean repair cost is between the bounds of the confidence interval.

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idom sample
devices, tne
nean repair cost was $60.00 and
Standard deviation was $14.00. Assume the population
normaily distributed and
distribution to find the margin or error and con
confidence interval for the population mean. Interpret the results.
The 95% confidence interval for the population mean p is ( ).
(Round to two decimal places as needed.)
The margin of error is $
(Round to two decimal places as needed.)
Interpret the results. Choose the correct answer below.
O A. If a large sample of mobile devices are taken approximately 95% of them will have repair costs between the bounds of the confidence interval.
O B. With 95% confidence, it can be said that the repair cost is between the bounds of the confidence interval.
OC. It can be said that 95% of mobile devices have a repair cost between the bounds of the confidence interval.
O D. With 95% confidence, it can be said that the population mean repair cost is between the bounds of the confidence interval.
Transcribed Image Text:idom sample devices, tne nean repair cost was $60.00 and Standard deviation was $14.00. Assume the population normaily distributed and distribution to find the margin or error and con confidence interval for the population mean. Interpret the results. The 95% confidence interval for the population mean p is ( ). (Round to two decimal places as needed.) The margin of error is $ (Round to two decimal places as needed.) Interpret the results. Choose the correct answer below. O A. If a large sample of mobile devices are taken approximately 95% of them will have repair costs between the bounds of the confidence interval. O B. With 95% confidence, it can be said that the repair cost is between the bounds of the confidence interval. OC. It can be said that 95% of mobile devices have a repair cost between the bounds of the confidence interval. O D. With 95% confidence, it can be said that the population mean repair cost is between the bounds of the confidence interval.
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