Identifying oxidizing and reducing agents 89°F Mostly sunny Decide whether each chemical reaction in the table below is an oxidation-reduction ("redox") reaction. If the reaction is a redox reaction, write down the formula of the reducing agent and the formula of the oxidizing agent. Fe(s) + CuSO, (aq)→ FeSO, (aq) + Cu(s) co₂(g) + 2H₂O() H₂O (aq) + HCO, (aq) Explanation - 2Na(s) + Cl₂ (8) 2NaCl(s) Check Q Search redox reaction? O yes reducing agent: 0 0 redox reaction? oxidizing agent: O yes reducing agent: oxidizing 0 agent: 0 Oyes reducing agent: oxidizing agent: O no redox reaction? 0 0 O no Ono LD- C X 03/5 3 Andrew V FEM do Ar © 2023 McGraw Hill LLC. All Rights Reserved Terms of Use Privacy Center Accessibi 920 2:53 PM C 7/30/2023

Identifying oxidizing and reducing agents 89°F Mostly sunny Decide whether each chemical reaction in the table below is an oxidation-reduction ("redox") reaction. If the reaction is a redox reaction, write down the formula of the reducing agent and the formula of the oxidizing agent. Fe(s) + CuSO, (aq)→ FeSO, (aq) + Cu(s) co₂(g) + 2H₂O() H₂O (aq) + HCO, (aq) Explanation - 2Na(s) + Cl₂ (8) 2NaCl(s) Check Q Search redox reaction? O yes reducing agent: 0 0 redox reaction? oxidizing agent: O yes reducing agent: oxidizing 0 agent: 0 Oyes reducing agent: oxidizing agent: O no redox reaction? 0 0 O no Ono LD- C X 03/5 3 Andrew V FEM do Ar © 2023 McGraw Hill LLC. All Rights Reserved Terms of Use Privacy Center Accessibi 920 2:53 PM C 7/30/2023

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Ch3 interconverting
Commun x Bb Blackboard Collaborate Ultra -2 X General Psychology-Fall 20 O X A ALEKS - Griffin Barden - Learn ww-awa.aleks.com/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-JcZzdcvSCzsqTCIDqNGV3bKqhMfPmUcQ4ENkmiXn9QCwgeDPDkQ06yszYWESPcekwL0-Qg619rekU7404HgFAGBEZaDr080?1oBw7QYjibavbSPXtx-YCjsh_7mMmrq#item O THERMOCHEMISTRY Griffin V Using Hess's Law to calculate net reaction enthalpy Nitric acid can be formed in two steps from the atmospheric gases nitrogen and oxygen, plus hydrogen prepared by reforming natural gas. In the first step, nitrogen and hydrogen react to form ammonia: N,(g) + 3 H,(g) → 2 NH3(g) AH=-92. kJ In the second step, ammonia and oxygen react to form nitric acid and water: NH3(g) + 20,(g) HNO3(g) H,O(g) AH=-330. kJ – + Calculate the net change in enthalpy for the formation of one mole of nitric acid from nitrogen, hydrogen and oxygen from these reactions. dla Round your answer to the nearest kJ. kJ
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Cou X A Ch 6 x C Sear X * Sear X Sear x b > Hov x2 Con x Con X b Sear X y! cher X M Inbc X M Inbc X + Vent X 8 https://www.saplinglearning.com/ibiscms/mod/flcn/view.php?id3D15033867 + Sapling Learning macmillan learning Ch 6 Homework Jason Bauer , Sapling Learning > Ventura College - Chem V30 (31510) - Spring21 - ALAWDI > Activities and Due Dates > Ch 6 Homework E 20 of 24 Questions O Assignment Score: O Resources O Hint 68.3% Check Answer O 16 Question 100% x2 Question 20 of 24 > 1 of 5 Attempts Correct How many moles of CaCl2 are in 7.76 x 1024 formula units? O 17 Question 100% x2 1 of 5 Attempts Correct 7.76 x 1024 formula units = mol O 18 Question 100% x2 2 of 5 Attempts Correct O 19 Question 1 of 5 Attempts 100% x2 Correct 20 Question 0% O of 5 Attempts 21 Question 0% x2 O of 5 Attempts © 2011-2021 Sapling Learning, Inc. about us careers privacy policy terms of use contact us help 1:42 PM P Type here to search 99+ 2/18/2021 19
Assessment-Chem 18-Gen (X 80 $ 54 R UCI General Chemistry Peer Tu X 65.2% Use the molar bond enthalpy data in the table to estimate the value of AHin for the equation CCI, (g) + 2 F₂ (g) →→→ CF₂(g) + 2Cl₂(g) The bonding in the molecules is shown. ΔΗ; = 888 F4 ++++ % 5 FS F-F A 6 New Tab MacBook Air ܀ T Y F6 & 7 CICI CI-CI A4 F7 * 8 ∞ Resources Average molar bond enthalpics. (Hond) kJ. mol Bond 464 C=N 142 N-H 351 N-N 502 N=N 730 N=N 347 F-F 615 811 414 439 331 276 293 615 Bond O-H 0-0 C-0 0=0 C=0 C-C C=C C=C C-H C-F C-CI C-Br C-N C=N DII FB 69 DD F9 kJ Question Source: McQuarrie, Rock, And Gallogly 4e-General Chemistry Publisher: University Science Books 1 0 ) CI-CI Br-Br H-H H-F H-CI H-Br H-S S-S 0 A F10 I' Check Answer P kJ. mol-1 890 390 159 418 945 155 243 192 435 565 431 368 364 225 3 F11 0 + Show All 411) F12 X }
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