Identify the LUMO in the MO diagram of O₂ (shown below). Op to t #*#* #9 A) o (2s orbitals) B) σ (2pz orbitals) C) TT (2px and 2py) D) TT* (2px and 2py) E) o* (2pz)

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**Identifying the LUMO in the MO Diagram of O₂**

The molecular orbital (MO) diagram of O₂ is illustrated with the energy levels of various orbitals. In this diagram:

- The lowest energy orbital is the σ (2s) orbital, represented by a pair of electrons.
- Followed by the σ\* (2s) orbital, also paired.
- Next are the π (2px and 2py) orbitals, each with two electrons (four in total).
- The π\* (2px and 2py) orbitals, each has one unpaired electron. These are the highest occupied molecular orbitals (HOMO).
- At the top of the diagram is the σ\* (2pz) orbital without any electrons.

The task is to identify the LUMO (Lowest Unoccupied Molecular Orbital) in this diagram. The LUMO is the next available orbital that can accept electrons. In this MO diagram, the LUMO is the σ\* (2pz) orbital.

**Options:**

A) σ (2s orbitals)

B) σ (2pz orbitals)

C) π (2px and 2py)

D) π\* (2px and 2py)

E) σ\* (2pz)

The correct answer is **E) σ\* (2pz)**.
Transcribed Image Text:**Identifying the LUMO in the MO Diagram of O₂** The molecular orbital (MO) diagram of O₂ is illustrated with the energy levels of various orbitals. In this diagram: - The lowest energy orbital is the σ (2s) orbital, represented by a pair of electrons. - Followed by the σ\* (2s) orbital, also paired. - Next are the π (2px and 2py) orbitals, each with two electrons (four in total). - The π\* (2px and 2py) orbitals, each has one unpaired electron. These are the highest occupied molecular orbitals (HOMO). - At the top of the diagram is the σ\* (2pz) orbital without any electrons. The task is to identify the LUMO (Lowest Unoccupied Molecular Orbital) in this diagram. The LUMO is the next available orbital that can accept electrons. In this MO diagram, the LUMO is the σ\* (2pz) orbital. **Options:** A) σ (2s orbitals) B) σ (2pz orbitals) C) π (2px and 2py) D) π\* (2px and 2py) E) σ\* (2pz) The correct answer is **E) σ\* (2pz)**.
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