**Question:**Identify the HOMO in the MO diagram of NO (shown below).**Diagram Description:**The diagram is a molecular orbital (MO) diagram for nitric oxide (NO). It consists of several molecular orbitals arranged vertically, indicating their energy levels. The orbitals are labeled as follows (from bottom to top):1. \( \sigma_s \) - Contains two electrons (paired).2. \( \sigma_s^* \) - Contains two electrons (paired).3. \( \pi_p \) (two orbitals) - Each contains two electrons (paired).4. \( \sigma_p \) - Contains two electrons (paired).5. \( \pi_p^* \) (two orbitals) - One orbital contains one electron (unpaired), the other is empty.6. \( \sigma_p^* \) - Empty**Answer Options:**A) \( \sigma \) (2s orbitals) B) \( \sigma \) (2pz orbitals) C) \( \pi \) (2px and 2py) D) \( \pi^* \) (2px or 2py) E) \( \sigma^* \) (2pz)**Explanation:**In molecular orbital theory, the Highest Occupied Molecular Orbital (HOMO) is the molecular orbital with the highest energy level that contains electrons. In this diagram, the HOMO is the \( \pi_p^* \) orbital with one unpaired electron. Therefore, the correct answer is:**D) \( \pi^* \) (2px or 2py)**

Ans. option D is correct answer

Answered: Identify the HOMO in the MO diagram of…

Identify the HOMO in the MO diagram of NO (shown below). A) o (2s orbitals) B) o (2pz orbitals) C) TT (2px and 2py) D) TT* (2px or 2py) E) o* (2pz)

Chemistry

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

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