Identify the correct half-reactions (a) and overall reaction (b) for a "Cu-Pb" voltaic cell. (a) Oxidation-Half Reaction: Pb(s) ----> Pb+2 + 2 e- Reduction-Half Reaction: Cu+2 + 2 e- ----> Cu (s)(b) Overall/Net Reaction: Pb (s) + Cu (s) ------> Pb+2(aq) + Cu+2 (aq) (a) Oxidation-Half Reaction: Pb+2 + 2 e- ----> Pb(s) Reduction-Half Reaction: Cu (s) ----> Cu+2 + 2 e- (b) Overall/Net Reaction: Pb (s) + Cu+2 (aq) ------> Pb+2(aq) + Cu (s) (a) Oxidation-Half Reaction: Pb+2 + 2 e- ----> Pb(s) Reduction-Half Reaction: Cu+2 ----> Cu (s) + 2 e- (b) Overall/Net Reaction: Pb (s) + Cu+2 (aq) ------> Pb+2(aq) + Cu (s) (a) Oxidation-Half Reaction: Pb(s) ----> Pb+2 + 2 e- Reduction-Half Reaction: Cu+2 + 2 e- ----> Cu (s)(b) Overall/Net Reaction: Pb (s) + Cu+2 (aq) ------> Pb+2(aq) + Cu (s)

Since the reduction potential for the two half reactions are Pb2+ + 2 e- ----> Pb…

Answered: Identify the correct half-reactions (a)…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Identify the correct half-reactions (a) and overall reaction (b) for a "Cu-Pb" voltaic cell.

		(a) Oxidation-Half Reaction: Pb(s) ----> Pb⁺² + 2 e^- Reduction-Half Reaction: Cu⁺² + 2 e^- ----> Cu (s) (b) Overall/Net Reaction: Pb (s) + Cu (s) ------> Pb⁺²(aq) + Cu⁺² (aq)
		(a) Oxidation-Half Reaction: Pb⁺² + 2 e^- ----> Pb(s) Reduction-Half Reaction: Cu (s) ----> Cu⁺² + 2 e^- (b) Overall/Net Reaction: Pb (s) + Cu⁺² (aq) ------> Pb⁺²(aq) + Cu (s)
		(a) Oxidation-Half Reaction: Pb⁺² + 2 e^- ----> Pb(s) Reduction-Half Reaction: Cu⁺² ----> Cu (s) + 2 e^- (b) Overall/Net Reaction: Pb (s) + Cu⁺² (aq) ------> Pb⁺²(aq) + Cu (s)
		(a) Oxidation-Half Reaction: Pb(s) ----> Pb⁺² + 2 e^- Reduction-Half Reaction: Cu⁺² + 2 e^- ----> Cu (s) (b) Overall/Net Reaction: Pb (s) + Cu⁺² (aq) ------> Pb⁺²(aq) + Cu (s)

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