ide the numerator and denominator by cos a cos ß. tan (x+3)= tan (x + ³) = cos a cos B cos a cos B wide each term in the numerator and denominator by cos a cos ß. = sin a cos a cos p + 1.1- COS α. cos a cos ß COS α. cos a cos ß 0-1+1.0 sin α cos a cos ß ... • tan B ▶►>>
ide the numerator and denominator by cos a cos ß. tan (x+3)= tan (x + ³) = cos a cos B cos a cos B wide each term in the numerator and denominator by cos a cos ß. = sin a cos a cos p + 1.1- COS α. cos a cos ß COS α. cos a cos ß 0-1+1.0 sin α cos a cos ß ... • tan B ▶►>>
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question

Transcribed Image Text:cos (a + B)
cosines, divide the numerator and denominator by cos a cos ß.
Divide the numerator and denominator by cos a cos ß.
tan (a + B)=
cos a cos B
tan (x + ³) =
cos a cos ß
Divide each term in the numerator and denominator by cos a cos ß.
sin α
cos a cos p
COS α.
+
COS α.
cos a cos ß
sin α.
cos a cos ß
cos a cos p
0·1+1.0
1.1-tan B
. After applying the formulas for sums of sines and
...
Simplify.

Transcribed Image Text:-4
Divide the numerator and denominator by cos a cos ß.
tan (x+3)=
cos a cos B
cos a cos B
Divide each term in the numerator and di
tan (x+3)=.
=
sin α.
cos a cos p
COS α.
cos a cos B
COS α.
COS & CO
sin α.
COS & CO
-1+1-7
1.1-tan B
Use the Pythagorean identities and simplify.
Use the even-odd identities and simplify.
Use the reciprocal identities and simplify.
Use the quotient identities and simplify.
Simplify.
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