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Ic, =-lcsar Icsar = 6 mA, VBE = 0.7 V, ICSAT lerini di %3D %3D VBC = -14.3 V, B = 100, VCEo 5VE, RC = 4RE, Ig = lco Ice %3D %3D Lütfen birini seçin. Vcc = 18 V, RB = 524.80 kN VCC a. VcC = 20 V, RB = 684.50 k. b. VCc = 20 V, RB 365.40 kN 644.80 kN VCC = 30 V, RB %3D %3D VCc = 30 V, RB = 876.70 k2

Ic, =-lcsar Icsar = 6 mA, VBE = 0.7 V, ICSAT lerini di %3D %3D VBC = -14.3 V, B = 100, VCEo 5VE, RC = 4RE, Ig = lco Ice %3D %3D Lütfen birini seçin. Vcc = 18 V, RB = 524.80 kN VCC a. VcC = 20 V, RB = 684.50 k. b. VCc = 20 V, RB 365.40 kN 644.80 kN VCC = 30 V, RB %3D %3D VCc = 30 V, RB = 876.70 k2

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Using the following design parameters for a bjt circuit design with emitter-biased configuration; Obtain Rb base resistor and Vcc DC bias voltage values.

Ic, =-lcsar Icsar = 6 mA, VBE = 0.7 V, ICSAT lerini di %3D %3D VBC = -14.3 V, B = 100, VCEo 5VE, RC = 4RE, Ig = lco Ice %3D %3D Lütfen birini seçin. Vcc = 18 V, RB = 524.80 kN VCC a. VcC = 20 V, RB = 684.50 k. b. VCc = 20 V, RB 365.40 kN 644.80 kN VCC = 30 V, RB %3D %3D VCc = 30 V, RB = 876.70 k2
Transcribed Image Text:Ic, =-lcsar Icsar = 6 mA, VBE = 0.7 V, ICSAT lerini di %3D %3D VBC = -14.3 V, B = 100, VCEo 5VE, RC = 4RE, Ig = lco Ice %3D %3D Lütfen birini seçin. Vcc = 18 V, RB = 524.80 kN VCC a. VcC = 20 V, RB = 684.50 k. b. VCc = 20 V, RB 365.40 kN 644.80 kN VCC = 30 V, RB %3D %3D VCc = 30 V, RB = 876.70 k2
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