IAR1 – €1 + IB(R2 + R3) = 0 - -IĄR1 + €1 + IB(R2 + R3) = 0 IAR1 – €1 – Ic(R5 + R4) + €2 = 0 €2 – IĄRĮ + €1 – Ic(R5 + R4) = 0 IA = IB + Ic А -IB(R2 + R3) – Ic(R4 + R5) + €2 = 0
IAR1 – €1 + IB(R2 + R3) = 0 - -IĄR1 + €1 + IB(R2 + R3) = 0 IAR1 – €1 – Ic(R5 + R4) + €2 = 0 €2 – IĄRĮ + €1 – Ic(R5 + R4) = 0 IA = IB + Ic А -IB(R2 + R3) – Ic(R4 + R5) + €2 = 0
Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter27: Direct-current Circuits
Section: Chapter Questions
Problem 22P: For the circuit shown in Figure P27.22, we wish to find the currents I1, I2, and I3. Use Kirchhoffs...
Related questions
Question
![IĄR1 – €1 + IB(R2 + R3) = 0
-
-IĄR1 + €1 + IB(R2 + R3) = 0
%3D
IĄR1 – €1 – Ic(R5 + R4) + €2
€2 – IĄR1 + €1 – Ic(R3 + R4) = 0
-
IA = IB + Ic
-IB(R2 + R3) – Ic(R4 + R5) + €2 = 0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5dcc9726-d2db-4331-a79b-138a0a6ca884%2Fc7861b60-2d8a-4833-8f76-9928d8b32da4%2Fqibangb_processed.png&w=3840&q=75)
Transcribed Image Text:IĄR1 – €1 + IB(R2 + R3) = 0
-
-IĄR1 + €1 + IB(R2 + R3) = 0
%3D
IĄR1 – €1 – Ic(R5 + R4) + €2
€2 – IĄR1 + €1 – Ic(R3 + R4) = 0
-
IA = IB + Ic
-IB(R2 + R3) – Ic(R4 + R5) + €2 = 0
![Consider a multi-loop circuit below. Select all correct equations describing Kirchhoff's rules for this
circuit.
- M-
E1
R1
R2
R3
IB
Ic
R5
R4
in
E2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5dcc9726-d2db-4331-a79b-138a0a6ca884%2Fc7861b60-2d8a-4833-8f76-9928d8b32da4%2Fk2dtk7j_processed.png&w=3840&q=75)
Transcribed Image Text:Consider a multi-loop circuit below. Select all correct equations describing Kirchhoff's rules for this
circuit.
- M-
E1
R1
R2
R3
IB
Ic
R5
R4
in
E2
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