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I. USING SUPERPOSITION THEOREM, FIND THE BRANCH CURRENT I2 IN THE CIRCUIT SHOWN. II. SOLVE THE SAME CURRENT USING SOURCE TRANSFORMATION THEOREM. R, = 22 E, = 4 V L R2 = 4 2 R3 = 16 2 I3 A I4 I5 E, =12 V = R = 10 2 R5 = 20 2 = E, = 8 V E ww ww

I. USING SUPERPOSITION THEOREM, FIND THE BRANCH CURRENT I2 IN THE CIRCUIT SHOWN. II. SOLVE THE SAME CURRENT USING SOURCE TRANSFORMATION THEOREM. R, = 22 E, = 4 V L R2 = 4 2 R3 = 16 2 I3 A I4 I5 E, =12 V = R = 10 2 R5 = 20 2 = E, = 8 V E ww ww

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Solve the subquestions and prove that I2 (superposition theorem) = I2 (source transformation theorem) 

I. USING SUPERPOSITION THEOREM, FIND THE BRANCH CURRENT I2 IN THE CIRCUIT SHOWN. II. SOLVE THE SAME CURRENT USING SOURCE TRANSFORMATION THEOREM. R, = 22 E, = 4 V B L R2 = 4 2 R3 = 16 2 I3 A I4 I5 E, =12 V = R4 = 10 2 R5 = 20 2 = E, = 8 V E D
Transcribed Image Text:I. USING SUPERPOSITION THEOREM, FIND THE BRANCH CURRENT I2 IN THE CIRCUIT SHOWN. II. SOLVE THE SAME CURRENT USING SOURCE TRANSFORMATION THEOREM. R, = 22 E, = 4 V B L R2 = 4 2 R3 = 16 2 I3 A I4 I5 E, =12 V = R4 = 10 2 R5 = 20 2 = E, = 8 V E D
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