I. Synthesize the corresponding alkyne from the given alkene. Show the steps (no need for the mechanism like transfer of electrons- just the arrowed steps) and the reagents needed in the steps CH3 -CH-CH=CH, CH;
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- OH 1. Hg(OAc)2, H2O 2. NaBH4 .CH3 .CH3 H2C H3C° Acid-catalyzed addition of water to an alkene yields an alcohol with Markovnikov regiochemistry. The electrophilic H* adds to the sp2 carbon with the most hydrogens to yield the most stable carbocation intermediate, which then adds water to give the product alcohol. Because a carbocation intermediate is formed, rearrangements can occur prior to the addition of water. To avoid the possibility of rearrangement and still give a Markovnikov alcohol, alkenes can instead be treated with mercury(II) acetate in aqueous THF and then subsequently reduced with sodium borohydride. This reaction proceeds through a cyclic mercurinium ion intermediate which cannot rearrange. Water adds to the cyclic intermediate at the most substituted carbon to give an organomercury alcohol. The reduction step with sodium borohydride is complex and involves radicals. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing…Which of the following reactions of alkenes is one-step reaction? O a. Bromination (treatment with Br2 in CHCI3) b. Hydrogenation (treatment with H2/Pt) O c. Acid-catalyzed hydration (treatment with aqueous H2SO4) d. Treatment with m- chloroperoxybenzoic acid followed reaction with aqueous acidic solutionOH 1. Hg(OAc)2, H2O 2. NABH4 CH3 .CH3 H2C H3C ČH3 CH3 Acid-catalyzed addition of water to an alkene yields an alcohol with Markovnikov regiochemistry. The electrophilic H adds to the sp carbon with the most hydrogens to yield the most stable carbocation intermediate, which then adds water to give the product alcohol. Because a carbocation intermediate is formed, rearrangements can occur prior to the addition of water. To avoid the possibility of rearrangement and still give a Markovnikov alcohol, alkenes can instead be treated with mercury(II) acetate in aqueous THF and then subsequently reduced with sodium borohydride. This reaction proceeds through a cyclic mercurinium ion intermediate which cannot rearrange. Water adds to the cyclic intermediate at the most substituted carbon to give an organomercury alcohol. The reduction step with sodium borohydride is complex and involves radicals. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing…
- (a) 2-methyl-2-pentanol Draw the structure of the alkene that was used to prepare the alcohol in highest yield. AAVIL ? ChemDoodleⓇ Which process does this employ? 1. Hg(OAc)2, H₂O; 2. NaBH4 01. BH3; 2. H₂O2, NaOH OsO4, H₂O2 On n [ ]#Predict the major product in each of the following reactions. Name the alkene reactant and the product, using IUPAC nomenclature. a. CH3 H Ni H C=C CH3 + H₂ H+ b. (CH,),C=CHCH,CH,CH, + H,O c. (CH3)₂C=CHCH3 + Br₂ ? d. CH3C(CH3)₂CH=CH₂ + HCl →? ?Q2. What are the products of the following reactions? Q3. 2-Bromopentane, when treated with alcoholic KOH yields a mixture of three alkenes A, B and C. Identify A, B and C. Which is predominant?
- ОН 1. H(OAc)2, На0 2. NABH4 .CH3 CH3 H2C H3C Acid-catalyzed addition of water to an alkene yields an alcohol with Markovnikov regiochemistry. The electrophilic H adds to the sp carbon with the most hydrogens to yield the most stable carbocation intermediate, which then adds water to give the product alcohol. Because a carbocation intermediate is formed, rearrangements can occur prior to the addition of water. To avoid the possibility of rearrangement and still give a Markovnikov alcohol, alkenes can instead be treated with mercury(II) acetate in aqueous THF and then subsequently reduced with sodium borohydride. This reaction proceeds through a cyclic mercurinium ion intermediate which cannot rearrange. Water adds to the cyclic intermediate at the most substituted carbon to give an organomercury alcohol. The reduction step with sodium borohydride is complex and involves radicals. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing…What are the possible starting materials of the given alkene below, if the starting material is heated at high temperature in the presence of concentrated acid? Assuming the reaction will not proceed towards carbon rearrangement of C=C double bond. CH3 -CH3 ČH3 CH3 CH3 CH3 CH3 OH П. III. IV. OH I. OH -CH3 -CH3 Но -CH3 ČH3 ČH3 ČH3 ČH3Illustrate the structure of the compounds using the following:A. major product between 1,4-dimethylcyclohex-1-ene and BH3, H202, OH-B. major product Of 4-methylpent-2-ene reacted with mCPBA, H20, H+C. major product between 1-methylcyclobut-1-ene and Br2 in dark conditionsD. alkene that formed propanone and carbon dioxide upon reaction with O3, Zn, H2O, H+
- (a) 2-methyl-2-pentanol Draw the structure of the alkene that was used to prepare the alcohol in highest yield. ? ChemDoodle Which process does this employ? 1. Hg(OAc)2, H₂O; 2. NaBH4 1. BH3; 2. H₂O2, NaOH OsO4, H₂O2 √ [FWhich stereoisomer would be produced from the reaction of trans-2-butene with OsO4 followed by H2O2? A. 2S,3S- diol and 2R, 3R-diol B. 2S,3R-diol and 2R,3S-diol C. 2S,3S-diol only D. 2R, 3R-diol only E. 2S,3R-diol only13. Predict the major product in each of the following reactions. Name the alkene reactant and the product, using IUPAC nomenclature. CH₂ H a. H CH₂ + H₂ Ni ? H+ b. (CH₂)₂C=CHCH₂CH₂CH₂ + H₂O e. (CH₂)₂C=CHCH, + Br₂ d. CH,C(CH₂)₂CH=CH₂ + HCI ? ? ?