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I. Solve for the unknown/s. 1. x:4 = (2x + 3) = 12 2. (x+ 1): (2x + 3) = (x + 3)(2x + 8) 3. (3x – 1): (3x + 1) = (x + 8): (x + 12) 4. (x + 2):3- 2: (5 - x)

I. Solve for the unknown/s. 1. x:4 = (2x + 3) = 12 2. (x+ 1): (2x + 3) = (x + 3)(2x + 8) 3. (3x – 1): (3x + 1) = (x + 8): (x + 12) 4. (x + 2):3- 2: (5 - x)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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1. Solve for the unknown/s. 1. x: 4 = (2x + 3) = 12 2. (x + 1): (2x + 3) = (x + 3)(2x + 8) 3. (3x - 1): (3x + 1) = (x + 8): (x + 12) 4. (x + 2):3 - 2: (5 - x)
Transcribed Image Text:1. Solve for the unknown/s. 1. x: 4 = (2x + 3) = 12 2. (x + 1): (2x + 3) = (x + 3)(2x + 8) 3. (3x - 1): (3x + 1) = (x + 8): (x + 12) 4. (x + 2):3 - 2: (5 - x)
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