I.Problem Solving: Answer what is being required. Show you complete solution.1. Compression test was applied to a certain type of wood. Compute the stress based on thefollowing dimensions. The grains are parallel with the length.а.Dimension (mm)Load (N)Compressive stress(МРa)Compression TestL = 50Parallel to the grainB = 75130,000W = 75L = 50Perpendicular to theB= 75W = 7535,000Grainb. What would be the shear stress for a single shear for the same data in a.?c. What is the modulus of rupture if the width of the specimen is 50mm, depth is

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I. Problem Solving: Answer what is being required. Show you complete solution. 1. Compression test was applied to a certain type of wood. Compute the stress based on the following dimensions. The grains are parallel with the length. а. Load (N) Compressive stress |(MPa) Compression Test Dimension (mm) L= 50 В - 75 W = 75 L= 50 Parallel to the grain 130,000 Perpendicular to the Grain B=75 35,000 W = 75

I. Problem Solving: Answer what is being required. Show you complete solution. 1. Compression test was applied to a certain type of wood. Compute the stress based on the following dimensions. The grains are parallel with the length. а. Load (N) Compressive stress |(MPa) Compression Test Dimension (mm) L= 50 В - 75 W = 75 L= 50 Parallel to the grain 130,000 Perpendicular to the Grain B=75 35,000 W = 75

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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I. Problem Solving: Answer what is being required. Show you complete solution. 1. Compression test was applied to a certain type of wood. Compute the stress based on the following dimensions. The grains are parallel with the length. а. Dimension (mm) Load (N) Compressive stress (MPa) Compression Test L= 50 Parallel to the grain В 3 75 130,000 W = 75 L = 50 Perpendicular to the Grain В - 75 W = 75 35,000 b. What would be the shear stress for a single shear for the same data in a.? c. What is the modulus of rupture if the width of the specimen is 50mm, depth is 50mm and the effective length is 30cm. The specimen failed at 24KN 2. A moisture test was conducted and the following weights were acquired before and after the wood was placed inside the oven for 24 hours. Initial weight 40g Final Weight 37g Moisture content
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