I. Given are some interesting information involving work, power and energy. Use what you know to solve the unknown quantities by simply filling up the blank. Right in the heart of China, the Macau Tower, Macau is the highest commercial bungee jump in the world with a maximum length of 233 m during stretch. When the bungee cord (rope) is unstretch, its length is 180m. If a man weighing 500 N, dropped from the top of Macau tower, moved vertically down, and reach the maximum length of 233m before the cord compressing up, what then is the (a) force constant of the bungee cord, and (b) what is the stopping power of the bungee cord? (assume that air resistance and mass of the bungee cord are negligible) Given: total length Weight of man3 m*g 500N,g 9.8 m/s² m = 233 m, un-stretch length = 180m, Ay= %3D Required: Force constant = ?, stopping power of Bungee cord = ? Solution: Solve for vr before the cord stretches: AGPE =mgh = AKE = 0.5m 2 = 2gh = 2*(9.8m/s2)*(180m) Solve for net acceleration due to the cord and earth's gravity; ahet= (u-v²)/(2Ay) Initial vis the final velocity before it stretches, while the new final V= 0 ahet = -33.3m/s? , Fnet = m*anet = Solve for time elapsed to fully stretch the bungee cord; At = ( (het) = Solve for the stopping power of the bungee cord: AW = 0.5k*Ay² , Pstop =AW/At AW = 0.5k*Ay2= V =V= Fnet = -k*Ay, k = -Fnet/Ay = %3D %3D Pstop =AW/At =

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Chapter1: Units, Trigonometry. And Vectors
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I. Given are some interesting information involving work, power and energy. Use what you know
to solve the unknown quantities by simply filling up the blank.
Right in the heart of China, the Macau Tower, Macau is the highest commercial bungee jump in the
world with a maximum length of 233 m during stretch. When the bungee cord (rope) is unstretch, its length is
180m. If a man weighing 500N, dropped from the top of Macau tower, moved vertically down, and reach the
maximum length of 233m before the cord compressing up, what then is the (a) force constant of the bungee
cord, and (b) what is the stopping power of the bungee cord? (assume that air resistance and mass of the
bungee cord are negligible)
Given:
total length = 233 m, un-stretch length = 180m, Ay=
Weight of man= m*g = 500N , g = 9.8 m/s? m =
%3D
%3D
%3D
%3D
%3D
Required: Force constant = ? , stopping power of Bungee cord = ?
Solution:
Solve for Vr before the cord stretches: AGPE =mgh = AKE = 0.5m
2 = 2gh = 2*(9.8m/s?)*(180m) =
Solve for net acceleration due to the cord and earth's gravity; anet= (-v²)/(2Ay)
Initial vis the final velocity before it stretches, while the new final Vf= 0
ahet = = m*anet =
%3D
- ΔΚΕ
%3D
V =Vf=
%3D
%3D
%3D
Fnet = -k*Ay, k = -Fnet/Ay =
-33.3m/s?, Fnet
Solve for time elapsed to fully stretch the bungee cord; At = (u -v)/(ahet) =
Solve for the stopping power of the bungee cord: AW = 0.5k*Ay² , Pstop =AW/At
AW = 0.5k*Ay2 =
%3D
%3D
%3D
%3D
Pstop =AW/At =
%3D
%3D
IL Conduct the activity entitled "Finding the Center of Mass" and answer the guide questions
Transcribed Image Text:I. Given are some interesting information involving work, power and energy. Use what you know to solve the unknown quantities by simply filling up the blank. Right in the heart of China, the Macau Tower, Macau is the highest commercial bungee jump in the world with a maximum length of 233 m during stretch. When the bungee cord (rope) is unstretch, its length is 180m. If a man weighing 500N, dropped from the top of Macau tower, moved vertically down, and reach the maximum length of 233m before the cord compressing up, what then is the (a) force constant of the bungee cord, and (b) what is the stopping power of the bungee cord? (assume that air resistance and mass of the bungee cord are negligible) Given: total length = 233 m, un-stretch length = 180m, Ay= Weight of man= m*g = 500N , g = 9.8 m/s? m = %3D %3D %3D %3D %3D Required: Force constant = ? , stopping power of Bungee cord = ? Solution: Solve for Vr before the cord stretches: AGPE =mgh = AKE = 0.5m 2 = 2gh = 2*(9.8m/s?)*(180m) = Solve for net acceleration due to the cord and earth's gravity; anet= (-v²)/(2Ay) Initial vis the final velocity before it stretches, while the new final Vf= 0 ahet = = m*anet = %3D - ΔΚΕ %3D V =Vf= %3D %3D %3D Fnet = -k*Ay, k = -Fnet/Ay = -33.3m/s?, Fnet Solve for time elapsed to fully stretch the bungee cord; At = (u -v)/(ahet) = Solve for the stopping power of the bungee cord: AW = 0.5k*Ay² , Pstop =AW/At AW = 0.5k*Ay2 = %3D %3D %3D %3D Pstop =AW/At = %3D %3D IL Conduct the activity entitled "Finding the Center of Mass" and answer the guide questions
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