i. Find the test statistic F i1. Find the degrees of freedom dfl and df2. Perform the test the hypotheses Ho:0 = 0 vs. H,:0 > až at the 5% level of significance. 111.
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![Q2.[5 points]: Two random samples taken from two normal populations yielded the following information:
Sample
Sample size
Sample variance
s = 53
s = 32
1
N1 = 16
2
N2 = 21
i.
Find the test statistic F
ii.
Find the degrees of freedom dfl and df2.
Perform the test the hypotheses Ho:0 = 0 vs. H,:o > ož at the 5% level of
significance.
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- Test the claim below about the mean of the differences for a population of paired data at the level of significance a. Assume the samples are random and dependent, and the populations are normally distributed. Claim: 0 В. Но На > 0 Ha: Ha s0 O C. Ho: Ha = 0 Ha: Hd #0 D. Ho: Ha <0 Ha: Hd 20 O E. Ho: Hd + 0 Ha: Hd F. Ho: Hd 20 Ha: Hd = 0 <0 The test statistic is t= (Round to two decimal places as needed.)use the t- distribution and the sample results to complete the test of the hypothesis. use a 5% significance level. Assume the results come from a random sample , and if the sample size is small, assume the underlying distribution is relatively normal . H0: miu=4 vs Ha: miu not equal to 4 using the sample results x bar =4.8 s= 2.3 with n=15. WHAT IS THE P-VALUE?fill in the blank
- Use the data below to test the claim that the weight loss was greater with the low fat diet compared to the low carbohydrate diet. Use a 5% level of significance. Low Fat Low Carbohydrate X = 4.71b X = 3.51b S1 = 7.21b "ị = 77 S1 = 6.91b n = 52 1. Identify the tail of the test. [ Select] 2. What is the P-value? [ Select] 3. Will the null hypothesis be rejected? [Select ] 4. Is the initial claim supported? [ Select]Please provide a clear and complete solution. Answer fast for I have 30 minutes left. Thank you very much.What is the critical t score if you are testing a one-tailed hypothesis, α level of .05 with df = 36? a. 1.671 b. 2.026 c. 2.028 d. 1.697
- 3/ a. Test the claim that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda. What are the null and alternative hypotheses? The test statistic, t, The P-value is State the conclusion for the test. A. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda. B. Reject the null hypothesis. There is not sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda. C. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda. D. Reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights…Test the claim below about the mean of the differences for a population of paired data at the level of significance a. Assume the samples are random and dependent, and the populations are normally distributed. Claim: H, 20; a = 0.05. Sample statistics: d = -2.2, s, = 1.5, n=14 Identify the null hypothesis by writing its complement. O A. Ho: Ha #0 Ha: H = 0 O B. Ho: Hg s0 Hgi Hg>0 O D. Ho: Ha 0 E. Ho: Ha 20 H: H <0 The test statistic is t= -5.49. (Round to two decimal places as needed.) The critical value(s) is(are) t, = - 1.77 (Round to two decimal places as needed. Use a comma to separate answers as needed.) V the rejection region, V the null hypothesis. There V statistically significant evidence to reject the claim. Since the test statistic isUse the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). K The test statistic in a right-tailed test is z=0.52. OA. 0.6030; fail to reject the null hypothesis OB. 0.0195; reject the null hypothesis OC. 0.3015; reject the null hypothesis OD. 0.3015; fail to reject the null hypothesis I Z 7 s 7 S x H command E D с III T R F G B Y I H U N B I J M G K O 6 H Time Remaining: 01:02:48 P command E . ? option Next
- Use a t-test to test the claim about the population mean u at the given level of significance a using the given sample statistics. Assume the population is normally distributed. Claim: u+ 29; a = 0.10 Sample statistics: x =30.3 , s 5.2, n = 11 What are the null and alternative hypotheses? Choose the correct answer below. A. H u#29 H u= 29 B. H: uz 29 H u 29 VD. H,: H= 29 H: u#29 correct: 0 What is the value of the standardized test statistic? The standardized test statistic is (Round to two decimal places as needed.)Application Exercise: Dr. Butler is interested in the preference for dog breeds among college students. She collected the observed frequencies below and wants to know if the breeds are equally preferred. What can be concluded with an a of 0.05? Irish Setter Golden Retriever Papillon Great Dane 101 94 135 97 L What is the appropriate test statistic? -Select Compute the statistic selected in : M Obtain/compute the appropriate values to make a decision about Hg. Critical Value = | J: Test Statistic = Decision: -Select- N Compute the corresponding effect size(s) and indicate magnitude(s). If not appropriate, input and/or select "na" below. Effect Size = | ]: Magnitude: -Select-- Make an interpretation based on the results. O There is a significant relationship between dog breeds and college students. There is a significant dog breed preference among college students. O Dog breeds are equally preferred among college students.Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). With H1: p≠0.377, the test statistic is z=3.06.
