I. AHrxn for the reaction below was determined using bond dissociation energies (BDES) to be -57 kJ. Using the table of BDE below, find the bond energy for H-Br. H H C=C H H + HBr Bond BDE (kJ/mol) H Br H-C-C-H HH C-C 348 C=C C-H 614 413 C-Br 276 II. Use heats of formation to find the standard heat of reaction (AH° rxn) for the reaction shown above. C₂H4 and HBr are both gases and AH°f for CH3CH₂Br (l) is -85.3 kJ/mol. Use T16-4-1 to find any additional values of AH°f needed. III. Why is there a dfference between the reaction enthalpies calculated by these different approaches?

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Solve part i, ii, and iii please thank you

I. AHrxn for the reaction below was determined using bond dissociation energies (BDES) to be -57 kJ. Using the table of BDE below,
find the bond energy for H-Br.
H H
C=C{ + HBr
H
Bond
BDE (kJ/mol)
H Br
IT
H-C-C-H
II
HH
C-C
348
C=C
614
C-H
413
C-Br
276
II. Use heats of formation to find the standard heat of reaction (AH°rxn) for the reaction shown above. C₂H4 and HBr are both gases
and AHf for CH3CH₂Br (l) is -85.3 kJ/mol. Use T16-4-1 to find any additional values of AHºf needed.
III. Why is there a dfference between the reaction enthalpies calculated by these different approaches?
Transcribed Image Text:I. AHrxn for the reaction below was determined using bond dissociation energies (BDES) to be -57 kJ. Using the table of BDE below, find the bond energy for H-Br. H H C=C{ + HBr H Bond BDE (kJ/mol) H Br IT H-C-C-H II HH C-C 348 C=C 614 C-H 413 C-Br 276 II. Use heats of formation to find the standard heat of reaction (AH°rxn) for the reaction shown above. C₂H4 and HBr are both gases and AHf for CH3CH₂Br (l) is -85.3 kJ/mol. Use T16-4-1 to find any additional values of AHºf needed. III. Why is there a dfference between the reaction enthalpies calculated by these different approaches?
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