I-x² f (x, y, 2) dz dy dx 1-x² Jo

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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sketch the region of integration

The image shows a triple integral, which is a way to integrate a function of three variables over a three-dimensional region. The integral is expressed as:

\[
\int_{0}^{1} \int_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}} \int_{0}^{2} f(x, y, z) \, dz \, dy \, dx
\]

This triple integral is set up as follows:

1. **Outer Integral: \(\int_{0}^{1} \ldots \, dx\)**
   - This represents the integration over the variable \(x\) from 0 to 1.

2. **Middle Integral: \(\int_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}} \ldots \, dy\)**
   - This represents the integration over \(y\) from \(-\sqrt{1-x^2}\) to \(\sqrt{1-x^2}\). This range indicates that the region for \(y\) is bounded by the curves dictated by \(x\), likely forming a circular or elliptical cross-section in a plane.

3. **Inner Integral: \(\int_{0}^{2} f(x, y, z) \, dz\)**
   - This represents the integration over \(z\) from 0 to 2. The function \(f(x, y, z)\) is integrated with respect to \(z\) in this range.

The function \(f(x, y, z)\) is not specified in the image, indicating that the form of \(f\) can be any function of three variables. This integral setup suggests a region in a three-dimensional space, where the \(xy\)-plane is bounded by a circular region and \(z\) is bounded by constant limits.
Transcribed Image Text:The image shows a triple integral, which is a way to integrate a function of three variables over a three-dimensional region. The integral is expressed as: \[ \int_{0}^{1} \int_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}} \int_{0}^{2} f(x, y, z) \, dz \, dy \, dx \] This triple integral is set up as follows: 1. **Outer Integral: \(\int_{0}^{1} \ldots \, dx\)** - This represents the integration over the variable \(x\) from 0 to 1. 2. **Middle Integral: \(\int_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}} \ldots \, dy\)** - This represents the integration over \(y\) from \(-\sqrt{1-x^2}\) to \(\sqrt{1-x^2}\). This range indicates that the region for \(y\) is bounded by the curves dictated by \(x\), likely forming a circular or elliptical cross-section in a plane. 3. **Inner Integral: \(\int_{0}^{2} f(x, y, z) \, dz\)** - This represents the integration over \(z\) from 0 to 2. The function \(f(x, y, z)\) is integrated with respect to \(z\) in this range. The function \(f(x, y, z)\) is not specified in the image, indicating that the form of \(f\) can be any function of three variables. This integral setup suggests a region in a three-dimensional space, where the \(xy\)-plane is bounded by a circular region and \(z\) is bounded by constant limits.
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we have to find the region of integration

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