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I would like to you help me with my homework because I struggled with step 6. Can you help me with step 6, please?

I would like to you help me with my homework because I struggled with step 6. Can you help me with step 6, please?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I would like to you help me with my homework because I struggled with step 6. Can you help me with step 6, please?
A₁ B₂ E₂=AB₂E₂ Molecular Shape of H₂S Step 1: Find the Central Atom Central atom is:__ (1) 5 Central atom A Look your line bond structure on page 1. AB₂E AB3E H H Step 3: Choose the ABE classification Circle the correct AB Ey notation. Recall, we use (A) to represent the central atom, (B) to represent the number of atoms bonded to the central atom, and (E) to represent the number of lone pairs AB₁E3 AB₁E2 AB₁E AB₂E2 AB2 AB3 AB4 Step 5: Use the Molecular Shape table from your notes to draw the ball and stick representation (2) H Batom surrounding central atom) lone E pair H Step 2: Count number of atoms bonded to the central atom (B) # of atoms bonded to central atom = B = Count number of lone pairs on the central atom (E) -2 # of lone pairs on central atom = E= Step 4: Use the Molecular Shape Table from your notes to select the molecular shape and bond angles. Molecular Shape- Bent =~110° Bond angles = Step 6: Determine Polarity Is the central atom surrounded by identical electron groups? Circle one: (yes) no If the answer was yes, then the molecule is nonpolar. If the answer is no, then the molecule is polar. Is the molecule polar? Circle one: yes no 19
Transcribed Image Text:A₁ B₂ E₂=AB₂E₂ Molecular Shape of H₂S Step 1: Find the Central Atom Central atom is:__ (1) 5 Central atom A Look your line bond structure on page 1. AB₂E AB3E H H Step 3: Choose the ABE classification Circle the correct AB Ey notation. Recall, we use (A) to represent the central atom, (B) to represent the number of atoms bonded to the central atom, and (E) to represent the number of lone pairs AB₁E3 AB₁E2 AB₁E AB₂E2 AB2 AB3 AB4 Step 5: Use the Molecular Shape table from your notes to draw the ball and stick representation (2) H Batom surrounding central atom) lone E pair H Step 2: Count number of atoms bonded to the central atom (B) # of atoms bonded to central atom = B = Count number of lone pairs on the central atom (E) -2 # of lone pairs on central atom = E= Step 4: Use the Molecular Shape Table from your notes to select the molecular shape and bond angles. Molecular Shape- Bent =~110° Bond angles = Step 6: Determine Polarity Is the central atom surrounded by identical electron groups? Circle one: (yes) no If the answer was yes, then the molecule is nonpolar. If the answer is no, then the molecule is polar. Is the molecule polar? Circle one: yes no 19
Expert Solution
Step 1

The molecular geometry of H2S is bent. In molecular geometry only bond pairs are considered.

The electron pair causes repulsion, therefore, the shape of H2S appears like bent molecular geometry.

The electron geometry for H2S is tetrahedral. In electronic geometry bond pair and lone pair both are considered.

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