I way to work the problem. √3 2 sec² x = 1 + cot² x Evaluate: sin-¹ sin 20 = 2 sin 0 sin² 0 = - tan³ 1-cos-0 2 - Evaluate: sec¹=2 X= tan(x³) - 8. Evaluate: tan-¹ 7. Simplify: secx cotx = 1 sin √3 2 1 Cos √√3 TC 7T 3 = -66.16° COS sin = CSC 9. sin(x+y)=sin x +sin y 10. sin² x = 1 - cos²x → √sin² x = √I - √cos²x = sin x = 1 - cos x

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