I want to count the number of nodes in a linked list. Each node of the list is a class called node. Each node of the list contains a pointer to the next node of the list called next. The variable start has the address of the first node in the list. If the list is empty start is set to null. The pointer at the end of the list is set to null. Which of the following code segments produces an accurate count of the nodes in the list. The answer is returned as an integer.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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I want to count the number of nodes in a linked list. Each node of the list is a class called node. Each node of the list contains a pointer to the next node of the list
called next. The variable start has the address of the first node in the list. If the list is empty start is set to null. The pointer t the end of the list is set to null. Which of
the following code segments produces an accurate count of the nodes in the list. The answer is returned as an integer.
O int count = 1;
node ptr start;
while(ptr != null){
ptr=ptr.next;
count++; }
return (count - 1);
Oint count = 1;
node ptr start;
while(ptr.next != null){
ptr-ptr.next;
count++; }
return count;
O int count = 0;
node ptr start;
while(ptr != null){
ptr-ptr.next;
count++; }
return count;
O int count = 0;
node ptr = null;
while(ptr != null){
ptr-ptr.next;
count++; }
return count;
Transcribed Image Text:I want to count the number of nodes in a linked list. Each node of the list is a class called node. Each node of the list contains a pointer to the next node of the list called next. The variable start has the address of the first node in the list. If the list is empty start is set to null. The pointer t the end of the list is set to null. Which of the following code segments produces an accurate count of the nodes in the list. The answer is returned as an integer. O int count = 1; node ptr start; while(ptr != null){ ptr=ptr.next; count++; } return (count - 1); Oint count = 1; node ptr start; while(ptr.next != null){ ptr-ptr.next; count++; } return count; O int count = 0; node ptr start; while(ptr != null){ ptr-ptr.next; count++; } return count; O int count = 0; node ptr = null; while(ptr != null){ ptr-ptr.next; count++; } return count;
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