I want the same solution, but with the mention of questions data and a detailed mathematical solution. Example 3.3 Determine the maximum buoyancy of a catheter that is inserted into the femoral artery of a patient and is passed through the cardiovascular system to the coronary artery (Fig. 3.6). The location where the catheter is inserted into the femoral artery is 50 cm below the aortic arch. The coronary artery is 5 cm below the aortic arch. Assume that the maximum buoyancy would occur at peak systole for a normal healthy individual (120 mmHg; this pressure is assumed to be measured at the aortic arch). Also assume that the catheter is perfectly cylindrical with a diameter of 2 mm. Aorta Catheter Femoral artery Example 3.3 (cont'd) Solution Pressure at indision: 1 m 100 cm 1 mmHg 133.32 Pa Pi = 120 mmHg+ (1050- 9.81 (50 cm) = 158.63 mmHg Pressure at coronary artery: Pi = 120 mmHg + ( 1050- m 1 m 100 cm 1 mmHg 133.32 Pa (5 cm) = 123.86 mmHg Volume of catheter from femoral artery to aortic arch: 2 mm (50

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I want the same solution, but with the mention of
questions data and a detailed mathematical
solution.
Example 3.3
Determine the maximum buoyancy of a catheter that is inserted into the femoral artery of a
patient and is passed through the cardiovascular system to the coronary artery (Fig. 3.6). The
location where the catheter is inserted into the femoral artery is 50 cm below the aortic arch.
The coronary artery is 5 cm below the aortic arch. Assume that the maximum buoyancy would
occur at peak systole for a normal healthy individual (120 mmHg; this pressure is assumed to
be measured at the aortic arch). Also assume that the catheter is perfectly cylindrical with a
diameter of 2 mm.
Aorta
Catheter
Femoral
artery
Example 3.3
(cont'd)
Solution
Pressure at indision:
120 mmHg + (1050) 9.81 (50 cm)
1 m
100 cm
1 mmHg
133.32 Pa
Pi =
= 158.63 mmHg
Pressure at coronary artery:
1 m
100 cm
1 mmHg
133.32 Pa
Pi = 120 mmHg +
1050-
(5 cm)
= 123.86 mmHg
Volume of catheter from femoral artery to aortic arch:
2 mm
(50 cm) = 157 cm
Volume of catheter from aortic arch to coronary artery:
2 mm
V =
(5 cm) = 0.157 cm
Buoyancy force on catheter:
(1050)(281)(157 m") + (1050)(. 51)(0.157 em")
F =
9.81
(1.57
(9.81
= 0.0178 N
Transcribed Image Text:I want the same solution, but with the mention of questions data and a detailed mathematical solution. Example 3.3 Determine the maximum buoyancy of a catheter that is inserted into the femoral artery of a patient and is passed through the cardiovascular system to the coronary artery (Fig. 3.6). The location where the catheter is inserted into the femoral artery is 50 cm below the aortic arch. The coronary artery is 5 cm below the aortic arch. Assume that the maximum buoyancy would occur at peak systole for a normal healthy individual (120 mmHg; this pressure is assumed to be measured at the aortic arch). Also assume that the catheter is perfectly cylindrical with a diameter of 2 mm. Aorta Catheter Femoral artery Example 3.3 (cont'd) Solution Pressure at indision: 120 mmHg + (1050) 9.81 (50 cm) 1 m 100 cm 1 mmHg 133.32 Pa Pi = = 158.63 mmHg Pressure at coronary artery: 1 m 100 cm 1 mmHg 133.32 Pa Pi = 120 mmHg + 1050- (5 cm) = 123.86 mmHg Volume of catheter from femoral artery to aortic arch: 2 mm (50 cm) = 157 cm Volume of catheter from aortic arch to coronary artery: 2 mm V = (5 cm) = 0.157 cm Buoyancy force on catheter: (1050)(281)(157 m") + (1050)(. 51)(0.157 em") F = 9.81 (1.57 (9.81 = 0.0178 N
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