I used Newton-Raphson's method to find the approximate root of the equation 0 = 1+ x3 - 5x and it was 0.5 x, so the approximate root at the second step is (a) X2 = 0.221568 (b) x2 = 0.201568 %3D X2 = 0.241568 None of the above is correct (d)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.1: Infinite Sequences And Summation Notation
Problem 68E
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I used Newton-Raphson's method to find the approximate root of the equation 0 = 1+ x3 - 5x and it was 0.5 = x, so the approximate root at the second step is
(a) x2 = 0.221568
(b) x2 = 0.201568
(c) x2 = 0.241568
None of the above is correct (d)
Transcribed Image Text:I used Newton-Raphson's method to find the approximate root of the equation 0 = 1+ x3 - 5x and it was 0.5 = x, so the approximate root at the second step is (a) x2 = 0.221568 (b) x2 = 0.201568 (c) x2 = 0.241568 None of the above is correct (d)
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