Can you please explain why the sigma part is added to solve the equation? It’s added first in line 5 of the image. 2) I =Put1 =1 =1 =1 =J =HSJ =1 = 172 = 4S8IS8sint.doSinudu8 (2) 4.82-1008-100→7 dx = dusinu.du.un=c42n+1 (+), du(2n+1)!을u2n=o (2n+1)!Cent)1÷8(+) du.a rajnn=o (2n+1)!.Sun du(-1)"2DF1Σn=o (n+1)! (2n+1)00 (4) (7x)20+1n=O (2n+1) (2n+1)!→dx=du

Answered: I= S sint.d 82

Math

Calculus

I= S sint.d 82

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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