I Review Part A- Transmitted power Learning Goal: To determine the maximum possible power transmission for a circular shaft and the minimum diameter required to avoid exceeding shear stress limits. A solid circular rod is used to transmit power from a motor to a machine. The diameter of the rod is D=2.25 in and the machine operates at w = 120 rpm. If the allowable shear stress in the shaft is 12 ksi, what is the maximum power transmissible to the machine? A rotating shaft can be used to transmit mechanical power from one place to another. For example, a shaft can be connected to a motor at one end and a pulley at the other. The shaft can then transmit power from the motor to the pulley. When the machine is operating, the shaft will rotate at some angular velocity w and will be subject to a torque T. The power transmitted by the shaft is P= Tw. Express your answer with appropriate units to three significant figures. > View Available Hint(s) ? The shaft's rotation can also be expressed as a frequency, f. which represents the number of revolutions of the shaft per unit time. The frequency and angular velocity are related by w= 2nf, so the power can also be calculated using P=2ñƒT. P = Value Units Submit When designing a shaft, one consideration is limits on shear Te stress. The torsion formula Tallow = relates the Part B - Minimum diameter allowable shear stress in a circular shaft with outer radiusc to the torque T. The polar moment of inertia is J ==e for 2 A solid circular shaft is required to transmit P = 43 kW from a motor to a machine. The maximum allowable stress in the shaft is Tallow = 75 MPa. If the machine runs at w = 16 rad/s , what is the minimum diameter for the shaft? a solid shaft. In the SI system, the units of torque are newton-meters ( N- m), and the units of power are watts ( 1 W=1N.m/s). In the FPS system, the basic units of torque are foot-pounds (ft - Ib), and the units of power are foot-pounds per second (ft - Ib/s). However, power is often expressed in horsepower, where 1 hp= 550 ft - lb/s. Express your answer in cm to three significant figures. > View Available Hint(s) Vo AEo | If vec ? D= cm

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Power Transmission
4 of 10
>
I Review
Part A - Transmitted power
Learning Goal:
To determine the maximum possible power transmission for a
circular shaft and the minimum diameter required to avoid
A solid circular rod is used to transmit power from a motor to a machine. The diameter of the rod is D= 2.25 in and the machine operates at w =
120 rpm . If the allowable shear stress in the shaft is 12 ksi , what is the maximum power transmissible to the machine?
exceeding shear stress limits.
A rotating shaft can be used to transmit mechanical power
from one place to another. For example, a shaft can be
connected to a motor at one end and a pulley at the other.
The shaft can then transmit power from the motor to the
pulley. When the machine is operating, the shaft will rotate at
some angular velocity w and will be subject to a torque T.
The power transmitted by the shaft is P = Tw.
Express your answer with appropriate units to three significant figures.
• View Available Hint(s)
μΑ
The shaft's rotation can also be expressed as a frequency, f,
which represents the number of revolutions of the shaft per
unit time. The frequency and angular velocity are related by
w = 2nf, so the power can also be calculated using
P= 2nfT.
P =
Value
Units
Submit
When designing a shaft, one consideration is limits on shear
Tc
stress. The torsion formula Tallow = - relates the
J
Part B - Minimum diameter
allowable shear stress in a circular shaft with outer radius c
to the torque T. The polar moment of inertia is J = cª for
2
A solid circular shaft is required to transmit P = 43 kW from a motor to a machine. The maximum allowable stress in the shaft is Tallow = 75
MPa . If the machine runs at w = 16 rad/s , what is the minimum diameter for the shaft?
a solid shaft.
In the SI system, the units of torque are newton-meters (
N. m), and the units of power are watts (
1 W=1N. m/s). In the FPS system, the basic units of
torque are foot-pounds (ft - lb), and the units of power are
foot-pounds per second (ft - lb/s). However, power is often
expressed in horsepower, where 1 hp = 550 ft · lb/s.
Express your answer in cm to three significant figures.
• View Available Hint(s)
ΑΣφ
vec
D =
cm
Transcribed Image Text:Power Transmission 4 of 10 > I Review Part A - Transmitted power Learning Goal: To determine the maximum possible power transmission for a circular shaft and the minimum diameter required to avoid A solid circular rod is used to transmit power from a motor to a machine. The diameter of the rod is D= 2.25 in and the machine operates at w = 120 rpm . If the allowable shear stress in the shaft is 12 ksi , what is the maximum power transmissible to the machine? exceeding shear stress limits. A rotating shaft can be used to transmit mechanical power from one place to another. For example, a shaft can be connected to a motor at one end and a pulley at the other. The shaft can then transmit power from the motor to the pulley. When the machine is operating, the shaft will rotate at some angular velocity w and will be subject to a torque T. The power transmitted by the shaft is P = Tw. Express your answer with appropriate units to three significant figures. • View Available Hint(s) μΑ The shaft's rotation can also be expressed as a frequency, f, which represents the number of revolutions of the shaft per unit time. The frequency and angular velocity are related by w = 2nf, so the power can also be calculated using P= 2nfT. P = Value Units Submit When designing a shaft, one consideration is limits on shear Tc stress. The torsion formula Tallow = - relates the J Part B - Minimum diameter allowable shear stress in a circular shaft with outer radius c to the torque T. The polar moment of inertia is J = cª for 2 A solid circular shaft is required to transmit P = 43 kW from a motor to a machine. The maximum allowable stress in the shaft is Tallow = 75 MPa . If the machine runs at w = 16 rad/s , what is the minimum diameter for the shaft? a solid shaft. In the SI system, the units of torque are newton-meters ( N. m), and the units of power are watts ( 1 W=1N. m/s). In the FPS system, the basic units of torque are foot-pounds (ft - lb), and the units of power are foot-pounds per second (ft - lb/s). However, power is often expressed in horsepower, where 1 hp = 550 ft · lb/s. Express your answer in cm to three significant figures. • View Available Hint(s) ΑΣφ vec D = cm
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