Homework Help is Here – Start Your Trial Now!
Science
Physics
I Review | Constants | Periodic Table Part A The law of reflection is quite useful for mirrors and other flat, shiny surfaces. (This sort of reflection is called specular reflection). However, you've likely been told that when you look at something, you are seeing light reflected from the object that you are looking at. This is reflection of a different sort: diffuse reflection. In this problem, you will see how diffuse reflection actually arises from the same law of reflection that you are accustomed to for reflections from mirrors. Consider a spotlight shining onto a horizontal mirror (Figure 1). If the light from the spotlight strikes the mirror at an angle 0, to the normal, what angle 0, to the normal would you expect for the reflected rays? Express your answer in terms of 0a. Submit Request Answer This simple rule of reflection no longer seems to hold for diffuse reflection. Consider the same spotlight but now reflecting from the surface of a table (Figure 2). Unlike the light reflected from the mirror, the light reflected from the table seems to go in all directions. If it didn't, then you'd only be able to see tables when you were at a specific angle to the lights above you! To understand why the light reflects in all directions, you must first look at a slightly simpler problem. Consider a flat surface, inclined downward from the horizontal by an angle a (Figure 3). The red line represents the surface and the red dotted line indicates the normal to this surface (the normal line). The two blue dashed lines represent horizontal and vertical. The angle between the incoming ray and the vertical is 0. Throughout this problem, assume that 0, is larger than a but smaller than 2a. (If you wish, you can determine the correct sign rules to generalize your results later.) • Part B Igure < 1 of 3 > Find the angle 0, between the reflected ray and the vertical. Express the angle between the reflected ray and the vertical in terms of a and 0. > View Available Hint(s) Submit Mirror

I Review | Constants | Periodic Table Part A The law of reflection is quite useful for mirrors and other flat, shiny surfaces. (This sort of reflection is called specular reflection). However, you've likely been told that when you look at something, you are seeing light reflected from the object that you are looking at. This is reflection of a different sort: diffuse reflection. In this problem, you will see how diffuse reflection actually arises from the same law of reflection that you are accustomed to for reflections from mirrors. Consider a spotlight shining onto a horizontal mirror (Figure 1). If the light from the spotlight strikes the mirror at an angle 0, to the normal, what angle 0, to the normal would you expect for the reflected rays? Express your answer in terms of 0a. Submit Request Answer This simple rule of reflection no longer seems to hold for diffuse reflection. Consider the same spotlight but now reflecting from the surface of a table (Figure 2). Unlike the light reflected from the mirror, the light reflected from the table seems to go in all directions. If it didn't, then you'd only be able to see tables when you were at a specific angle to the lights above you! To understand why the light reflects in all directions, you must first look at a slightly simpler problem. Consider a flat surface, inclined downward from the horizontal by an angle a (Figure 3). The red line represents the surface and the red dotted line indicates the normal to this surface (the normal line). The two blue dashed lines represent horizontal and vertical. The angle between the incoming ray and the vertical is 0. Throughout this problem, assume that 0, is larger than a but smaller than 2a. (If you wish, you can determine the correct sign rules to generalize your results later.) • Part B Igure < 1 of 3 > Find the angle 0, between the reflected ray and the vertical. Express the angle between the reflected ray and the vertical in terms of a and 0. > View Available Hint(s) Submit Mirror

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
See similar textbooks
icon
Related questions
Question

please help with both parts

Diffuse Reflection 3 of 24 I Review | Constants | Periodic Table Part A The law of reflection is quite useful for mirrors and other flat, shiny surfaces. (This sort of reflection is called specular reflection). However, you've likely been told that when you look at something, you are seeing light reflected from the object that you are looking at. This is reflection of a different sort: diffuse reflection. In this problem, you will see how diffuse reflection actually arises from the same law of reflection that you are accustomed to for reflections from mirrors. Consider a spotlight shining onto a horizontal mirror (Figure 1). If the light from the spotlight strikes the mirror at an angle 0a to the normal, what angle 0, to the normal would you expect for the reflected rays? Express your answer in terms of 0a. O, = Submit Request Answer This simple rule of reflection no longer seems to hold for diffuse reflection. Consider the same spotlight but now reflecting from the surface of a table (Figure 2). Unlike the light reflected from the mirror, the light reflected from the table seems to go in all directions. If it didn't, then you'd only be able to see tables when you were at a specific angle to the lights above you! To understand why the light reflects in all directions, you must first look at a slightly simpler problem. Consider a flat surface, inclined downward from the horizontal by an angle a (Figure 3). The red line represents the surface and the red dotted line indicates the normal to this surface (the normal line). The two blue dashed lines represent horizontal and vertical. The angle between the incoming ray and the vertical is Oa. Throughout this problem, assume that 0a is larger than a but smaller than 2a. (If you wish, you can determine the correct sign rules to generalize your results later.) Part B Figure 1 of 3 Find the angle 0, between the reflected ray and the vertical. Express the angle between the reflected ray and the vertical in terms of a and Oa. • View Available Hint(s) ΑΣΦ ? O, = Submit Mirror
Transcribed Image Text:Diffuse Reflection 3 of 24 I Review | Constants | Periodic Table Part A The law of reflection is quite useful for mirrors and other flat, shiny surfaces. (This sort of reflection is called specular reflection). However, you've likely been told that when you look at something, you are seeing light reflected from the object that you are looking at. This is reflection of a different sort: diffuse reflection. In this problem, you will see how diffuse reflection actually arises from the same law of reflection that you are accustomed to for reflections from mirrors. Consider a spotlight shining onto a horizontal mirror (Figure 1). If the light from the spotlight strikes the mirror at an angle 0a to the normal, what angle 0, to the normal would you expect for the reflected rays? Express your answer in terms of 0a. O, = Submit Request Answer This simple rule of reflection no longer seems to hold for diffuse reflection. Consider the same spotlight but now reflecting from the surface of a table (Figure 2). Unlike the light reflected from the mirror, the light reflected from the table seems to go in all directions. If it didn't, then you'd only be able to see tables when you were at a specific angle to the lights above you! To understand why the light reflects in all directions, you must first look at a slightly simpler problem. Consider a flat surface, inclined downward from the horizontal by an angle a (Figure 3). The red line represents the surface and the red dotted line indicates the normal to this surface (the normal line). The two blue dashed lines represent horizontal and vertical. The angle between the incoming ray and the vertical is Oa. Throughout this problem, assume that 0a is larger than a but smaller than 2a. (If you wish, you can determine the correct sign rules to generalize your results later.) Part B Figure 1 of 3 Find the angle 0, between the reflected ray and the vertical. Express the angle between the reflected ray and the vertical in terms of a and Oa. • View Available Hint(s) ΑΣΦ ? O, = Submit Mirror
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Polarisation of light
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON
SEE MORE TEXTBOOKS