I Review | Constants | Periodic Table involving transition of the electron from two energy states ny to ng is given as ΔΕ=-(2.18 x 10-18 J) x (-) Niels Bohr is credited with deriving this form of the Rydberg equation, which is sometimes called Bohr's equation Part B What is the change in energy, AE, in kilojoules per mole of hydrogen atoms for an electron transition from n-4 to n= 2? Express your answer in kilojoules per mole to three significant figures. > View Available Hint(s) x" X•10" AE = - 301 kJ/mol
I Review | Constants | Periodic Table involving transition of the electron from two energy states ny to ng is given as ΔΕ=-(2.18 x 10-18 J) x (-) Niels Bohr is credited with deriving this form of the Rydberg equation, which is sometimes called Bohr's equation Part B What is the change in energy, AE, in kilojoules per mole of hydrogen atoms for an electron transition from n-4 to n= 2? Express your answer in kilojoules per mole to three significant figures. > View Available Hint(s) x" X•10" AE = - 301 kJ/mol
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
100%
![# Chapter 8 Problem Set
## Derivations from the Rydberg Equation
The Rydberg equation expresses the wavelength, λ, of emitted light based on the initial and final energy states (n₁ and n₂) of an electron in a hydrogen atom:
\[
\frac{1}{\lambda} = R_H \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right)
\]
where
\[
R_H = 1.097 \times 10^7 \, \text{m}^{-1} = 1.097 \times 10^{-2} \, \text{nm}^{-1}
\]
You may also see this equation written as:
\[
\frac{1}{\lambda} = -R_H \left( \frac{1}{n_2^2} - \frac{1}{n_1^2} \right)
\]
Since
\[
\frac{1}{n_1^2} - \frac{1}{n_2^2} = -\left( \frac{1}{n_2^2} - \frac{1}{n_1^2} \right)
\]
The two formulas are equivalent and sometimes used interchangeably. It can help to remember that when light is emitted, E is negative. When light is absorbed, E is positive.
### Energy Change
The change in energy, ΔE, involving the transition of the electron from two energy states n₀ to n₁, is given as:
\[
\Delta E = \left(-2.18 \times 10^{-18} \, \text{J} \right) \times \left( \frac{1}{n_1^2} - \frac{1}{n_0^2} \right)
\]
Niels Bohr is credited with deriving this form of the Rydberg equation, which is sometimes called Bohr's equation.
### Part B
What is the change in energy, ΔE, in kilojoules per mole of hydrogen atoms for an electron transition from n = 4 to n = 2? Express your answer in kilojoules per mole to three significant figures.
**Answer Input:**
ΔE = \[ \boxed{301} \, \text{kJ/mol](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff405cacd-b73c-4ff5-aae6-a678a4b84912%2F78b53c8a-7530-4fc6-90d4-5ff7b840a9fa%2Futheqc4_processed.jpeg&w=3840&q=75)
Transcribed Image Text:# Chapter 8 Problem Set
## Derivations from the Rydberg Equation
The Rydberg equation expresses the wavelength, λ, of emitted light based on the initial and final energy states (n₁ and n₂) of an electron in a hydrogen atom:
\[
\frac{1}{\lambda} = R_H \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right)
\]
where
\[
R_H = 1.097 \times 10^7 \, \text{m}^{-1} = 1.097 \times 10^{-2} \, \text{nm}^{-1}
\]
You may also see this equation written as:
\[
\frac{1}{\lambda} = -R_H \left( \frac{1}{n_2^2} - \frac{1}{n_1^2} \right)
\]
Since
\[
\frac{1}{n_1^2} - \frac{1}{n_2^2} = -\left( \frac{1}{n_2^2} - \frac{1}{n_1^2} \right)
\]
The two formulas are equivalent and sometimes used interchangeably. It can help to remember that when light is emitted, E is negative. When light is absorbed, E is positive.
### Energy Change
The change in energy, ΔE, involving the transition of the electron from two energy states n₀ to n₁, is given as:
\[
\Delta E = \left(-2.18 \times 10^{-18} \, \text{J} \right) \times \left( \frac{1}{n_1^2} - \frac{1}{n_0^2} \right)
\]
Niels Bohr is credited with deriving this form of the Rydberg equation, which is sometimes called Bohr's equation.
### Part B
What is the change in energy, ΔE, in kilojoules per mole of hydrogen atoms for an electron transition from n = 4 to n = 2? Express your answer in kilojoules per mole to three significant figures.
**Answer Input:**
ΔE = \[ \boxed{301} \, \text{kJ/mol
Expert Solution

Step 1
Given;
Step by step
Solved in 4 steps with 3 images

Recommended textbooks for you

Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning

Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education

Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning

Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning

Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education

Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning

Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education

Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning

Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY