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I Review | Constant Learning Goal: In this tutorial, you will practice the calculation of power in circuits containing loads, including the effects of non- ideal transmission lines, and practice how to improve the power factor for an entire system. Part A - Power and power factor for parallel loads I Consider the two loads in the circuit in (Figure 1). Load #1 (L1) absorbs S = 57 kVA at a leading power factor of pfi = 0.57. Load #2 (L2) absorbs S2 = 56 kVA at a lagging power factor of pf2 = 0.71. Use this information to calculate the real (P) and reactive (Q) power provided by the V, = 300 V-rms 60 Hz source and its power factor (pf). Many appliances (e.g., hair dryers, coffee makers, and refrigerators) and industrial loads are powered by AC sources. The ability to be able to calculate their power needs is important in a number of situations. Before completing this tutorial, make sure you are familiar with the relationships between average, reactive, and apparent power and the power factor. Express your answers numerically to three significant figures separated by commas. • View Available Hint(s) VO AEO !t vec P, Q. pf = kW. KVAR, no unit Submit Part B - Power for a parallel load with a transmission line impedance Consider the circuit in (Figure 2). The load (L1) absorbs P = 33 W and Q = 23 VAR of power. Use this information to calculate complex power provided by the source if the voltage across the load is V, = 475 V-rms 60 Hz source and the impedance of the transmission line is 0.030 + j(-0.020) N. Figure 1 of 2 > Express your answer in rectangular complex form to three significant figures. • View Available Hint(s) Va AEo !t vec ? S = VA V() L1 L2 Submit

I Review | Constant Learning Goal: In this tutorial, you will practice the calculation of power in circuits containing loads, including the effects of non- ideal transmission lines, and practice how to improve the power factor for an entire system. Part A - Power and power factor for parallel loads I Consider the two loads in the circuit in (Figure 1). Load #1 (L1) absorbs S = 57 kVA at a leading power factor of pfi = 0.57. Load #2 (L2) absorbs S2 = 56 kVA at a lagging power factor of pf2 = 0.71. Use this information to calculate the real (P) and reactive (Q) power provided by the V, = 300 V-rms 60 Hz source and its power factor (pf). Many appliances (e.g., hair dryers, coffee makers, and refrigerators) and industrial loads are powered by AC sources. The ability to be able to calculate their power needs is important in a number of situations. Before completing this tutorial, make sure you are familiar with the relationships between average, reactive, and apparent power and the power factor. Express your answers numerically to three significant figures separated by commas. • View Available Hint(s) VO AEO !t vec P, Q. pf = kW. KVAR, no unit Submit Part B - Power for a parallel load with a transmission line impedance Consider the circuit in (Figure 2). The load (L1) absorbs P = 33 W and Q = 23 VAR of power. Use this information to calculate complex power provided by the source if the voltage across the load is V, = 475 V-rms 60 Hz source and the impedance of the transmission line is 0.030 + j(-0.020) N. Figure 1 of 2 > Express your answer in rectangular complex form to three significant figures. • View Available Hint(s) Va AEo !t vec ? S = VA V() L1 L2 Submit

Power System Analysis and Design (MindTap Course List)
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
Section: Chapter Questions
Problem 2.16P: A single-phase, 120V(rms),60Hz source supplies power to a series R-L circuit consisting of R=10 and...
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Solve for parts A & C.

I Review | Constant Learning Goal: In this tutorial, you will practice the calculation of power in circuits containing loads, including the effects of non- ideal transmission lines, and practice how to improve the power factor for an entire system. Part A - Power and power factor for parallel loads I Consider the two loads in the circuit in (Figure 1). Load #1 (L1) absorbs S = 57 kVA at a leading power factor of pfi = 0.57. Load #2 (L2) absorbs S2 = 56 kVA at a lagging power factor of pf2 = 0.71. Use this information to calculate the real (P) and reactive (Q) power provided by the V, = 300 V-rms 60 Hz source and its power factor (pf). Many appliances (e.g., hair dryers, coffee makers, and refrigerators) and industrial loads are powered by AC sources. The ability to be able to calculate their power needs is important in a number of situations. Before completing this tutorial, make sure you are familiar with the relationships between average, reactive, and apparent power and the power factor. Express your answers numerically to three significant figures separated by commas. • View Available Hint(s) VO AEO !t vec P, Q. pf = kW. KVAR, no unit Submit Part B - Power for a parallel load with a transmission line impedance Consider the circuit in (Figure 2). The load (L1) absorbs P = 33 W and Q = 23 VAR of power. Use this information to calculate complex power provided by the source if the voltage across the load is V, = 475 V-rms 60 Hz source and the impedance of the transmission line is 0.030 + j(-0.020) N. Figure 1 of 2 > Express your answer in rectangular complex form to three significant figures. • View Available Hint(s) Va AEo !t vec ? S = VA V() L1 L2 Submit
Transcribed Image Text:I Review | Constant Learning Goal: In this tutorial, you will practice the calculation of power in circuits containing loads, including the effects of non- ideal transmission lines, and practice how to improve the power factor for an entire system. Part A - Power and power factor for parallel loads I Consider the two loads in the circuit in (Figure 1). Load #1 (L1) absorbs S = 57 kVA at a leading power factor of pfi = 0.57. Load #2 (L2) absorbs S2 = 56 kVA at a lagging power factor of pf2 = 0.71. Use this information to calculate the real (P) and reactive (Q) power provided by the V, = 300 V-rms 60 Hz source and its power factor (pf). Many appliances (e.g., hair dryers, coffee makers, and refrigerators) and industrial loads are powered by AC sources. The ability to be able to calculate their power needs is important in a number of situations. Before completing this tutorial, make sure you are familiar with the relationships between average, reactive, and apparent power and the power factor. Express your answers numerically to three significant figures separated by commas. • View Available Hint(s) VO AEO !t vec P, Q. pf = kW. KVAR, no unit Submit Part B - Power for a parallel load with a transmission line impedance Consider the circuit in (Figure 2). The load (L1) absorbs P = 33 W and Q = 23 VAR of power. Use this information to calculate complex power provided by the source if the voltage across the load is V, = 475 V-rms 60 Hz source and the impedance of the transmission line is 0.030 + j(-0.020) N. Figure 1 of 2 > Express your answer in rectangular complex form to three significant figures. • View Available Hint(s) Va AEo !t vec ? S = VA V() L1 L2 Submit
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