**PHY 220 - University Physics with Lab I**---**Chapter 8 MP****Problem 8.22****Scenario:**A student has 69-cm-long arms.**Question:****Part A**What is the minimum angular velocity (in rpm) for swinging a bucket of water in a vertical circle without spilling any? The distance from the handle to the bottom of the bucket is 35 cm. Express your answer using two significant figures.**Input Box:**- Placeholder for expressing angular velocity in rpm with a visual interface for input.- Pre-filled value: 30.5 rpm**Feedback:**- Red X indicating an incorrect response.- Message: "Incorrect; Try Again; 3 attempts remaining"**Options:**- Submit Button- Previous Answers- Request Answer---This layout helps students understand the physics problem's parameters, and provides a space for interactive input and feedback on their calculations.

Here the centripetal force will keep the bucket and water in a circular path,At the minimum speed the weight of the water provides the centripetal force, then mg=mrω2ω2=grω=gr=9.8 m/s20.69+0.35 m=3.07 rad/s=3.07 rad/s×602πrpmrad/s≈0.29×102 rpm

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I Review I Constants A student has 69-cm-long arms. Part A What is the minimum angular velocity (in rpm) for swinging a bucket of water in a vertical circle without spilling any? The distance from the handle to the bottom of the bucket is 35 cm

I Review I Constants A student has 69-cm-long arms. Part A What is the minimum angular velocity (in rpm) for swinging a bucket of water in a vertical circle without spilling any? The distance from the handle to the bottom of the bucket is 35 cm

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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