I Review A particle with a charge of 18 µC experiences a force of 2.9x10¬4 N when it moves at right angles to a magnetic field with a speed of 28 m/s. Part A What force does this particle experience when it moves with a speed of 6.2 m/s at an angle of 25 ° relative to the magnetic field? Express your answer using two significant figures. F =
I Review A particle with a charge of 18 µC experiences a force of 2.9x10¬4 N when it moves at right angles to a magnetic field with a speed of 28 m/s. Part A What force does this particle experience when it moves with a speed of 6.2 m/s at an angle of 25 ° relative to the magnetic field? Express your answer using two significant figures. F =
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Physics Problem: Magnetic Force on a Particle**
**Given:**
- A particle with a charge of \(18 \, \mu \text{C}\) (microcoulombs) experiences a force of \(2.9 \times 10^{-4} \, \text{N}\) (Newtons) when it moves at right angles to a magnetic field with a speed of \(28 \, \text{m/s}\).
**Question (Part A):**
- What force does this particle experience when it moves with a speed of \(6.2 \, \text{m/s}\) at an angle of \(25^\circ\) relative to the magnetic field?
- **Instruction:** Express your answer using two significant figures.
**Response Box:**
- \( F = \) [Answer in Newtons]
- **Submit Button:** Submit your answer.
**Features:**
- Various tools are available to input answers, including a palette for symbols and a request for answer button.
- Option to provide feedback on the question.
This problem involves calculating the magnetic force on a charged particle moving through a magnetic field. The force depends on the charge, speed, angle with the magnetic field, and the magnetic field strength. The formula used is \( F = qvB\sin\theta \), where \( q \) is charge, \( v \) is speed, \( B \) is the magnetic field, and \( \theta \) is the angle between the velocity and magnetic field directions.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F81f7b2d1-b7ba-44aa-b963-9939c9f44db6%2F455609a3-7ca4-4ded-9845-b982be7be2ef%2Fvt371k6_processed.png&w=3840&q=75)
Transcribed Image Text:**Physics Problem: Magnetic Force on a Particle**
**Given:**
- A particle with a charge of \(18 \, \mu \text{C}\) (microcoulombs) experiences a force of \(2.9 \times 10^{-4} \, \text{N}\) (Newtons) when it moves at right angles to a magnetic field with a speed of \(28 \, \text{m/s}\).
**Question (Part A):**
- What force does this particle experience when it moves with a speed of \(6.2 \, \text{m/s}\) at an angle of \(25^\circ\) relative to the magnetic field?
- **Instruction:** Express your answer using two significant figures.
**Response Box:**
- \( F = \) [Answer in Newtons]
- **Submit Button:** Submit your answer.
**Features:**
- Various tools are available to input answers, including a palette for symbols and a request for answer button.
- Option to provide feedback on the question.
This problem involves calculating the magnetic force on a charged particle moving through a magnetic field. The force depends on the charge, speed, angle with the magnetic field, and the magnetic field strength. The formula used is \( F = qvB\sin\theta \), where \( q \) is charge, \( v \) is speed, \( B \) is the magnetic field, and \( \theta \) is the angle between the velocity and magnetic field directions.
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