I Review A particle with a charge of 18 µC experiences a force of 2.9x10¬4 N when it moves at right angles to a magnetic field with a speed of 28 m/s. Part A What force does this particle experience when it moves with a speed of 6.2 m/s at an angle of 25 ° relative to the magnetic field? Express your answer using two significant figures. F =

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Chapter1: Units, Trigonometry. And Vectors
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**Physics Problem: Magnetic Force on a Particle**

**Given:**

- A particle with a charge of \(18 \, \mu \text{C}\) (microcoulombs) experiences a force of \(2.9 \times 10^{-4} \, \text{N}\) (Newtons) when it moves at right angles to a magnetic field with a speed of \(28 \, \text{m/s}\).

**Question (Part A):**

- What force does this particle experience when it moves with a speed of \(6.2 \, \text{m/s}\) at an angle of \(25^\circ\) relative to the magnetic field?

- **Instruction:** Express your answer using two significant figures.

**Response Box:**

- \( F = \) [Answer in Newtons]

- **Submit Button:** Submit your answer.

**Features:**

- Various tools are available to input answers, including a palette for symbols and a request for answer button.
- Option to provide feedback on the question.

This problem involves calculating the magnetic force on a charged particle moving through a magnetic field. The force depends on the charge, speed, angle with the magnetic field, and the magnetic field strength. The formula used is \( F = qvB\sin\theta \), where \( q \) is charge, \( v \) is speed, \( B \) is the magnetic field, and \( \theta \) is the angle between the velocity and magnetic field directions.
Transcribed Image Text:**Physics Problem: Magnetic Force on a Particle** **Given:** - A particle with a charge of \(18 \, \mu \text{C}\) (microcoulombs) experiences a force of \(2.9 \times 10^{-4} \, \text{N}\) (Newtons) when it moves at right angles to a magnetic field with a speed of \(28 \, \text{m/s}\). **Question (Part A):** - What force does this particle experience when it moves with a speed of \(6.2 \, \text{m/s}\) at an angle of \(25^\circ\) relative to the magnetic field? - **Instruction:** Express your answer using two significant figures. **Response Box:** - \( F = \) [Answer in Newtons] - **Submit Button:** Submit your answer. **Features:** - Various tools are available to input answers, including a palette for symbols and a request for answer button. - Option to provide feedback on the question. This problem involves calculating the magnetic force on a charged particle moving through a magnetic field. The force depends on the charge, speed, angle with the magnetic field, and the magnetic field strength. The formula used is \( F = qvB\sin\theta \), where \( q \) is charge, \( v \) is speed, \( B \) is the magnetic field, and \( \theta \) is the angle between the velocity and magnetic field directions.
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