I Re Light from a helium-neon laser (A = 633 nm) is used to illuminate two narrow slits. The interference pattern is observed on a screen 2.8 m behind the slits. Twelve bright fringes are seen, spanning a distance of 55 mm . Part A What is the spacing (in mm) between the slits? Express your answer using two significant figures. ? d = .0805 mm
I Re Light from a helium-neon laser (A = 633 nm) is used to illuminate two narrow slits. The interference pattern is observed on a screen 2.8 m behind the slits. Twelve bright fringes are seen, spanning a distance of 55 mm . Part A What is the spacing (in mm) between the slits? Express your answer using two significant figures. ? d = .0805 mm
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Interference Pattern Analysis Using a Helium-Neon Laser**
**Experimental Setup Description:**
Light from a helium-neon laser (\(\lambda = 633 \, \text{nm}\)) is utilized to illuminate two narrow slits. The resulting interference pattern is projected onto a screen positioned 2.8 meters behind the slits. The pattern displays twelve bright fringes stretching across a distance of 55 millimeters.
**Problem Statement (Part A):**
Determine the spacing (in millimeters) between the slits.
**Instructions:**
Provide your answer using two significant figures.
**Solution:**
The spacing between the slits is calculated as follows:
\[ d = 0.0805 \, \text{mm} \]
This solution assumes a baseline understanding of interference patterns and the application of relevant physics equations to solve for slit spacing. For educational purposes, the method to solve for \(d\) involves the use of the fringe spacing formula:
\[ d = \frac{m\lambda L}{x} \]
Where:
- \(d\) is the spacing between the slits
- \(\lambda\) is the wavelength of the light
- \(L\) is the distance from the slits to the screen
- \(x\) is the distance over which the fringes are observed
- \(m\) is the number of fringes
This exercise provides a practical application of theoretical physics concepts in the field of optics.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7ae8af9d-8b9c-47c5-b693-2ca69a82702b%2Fdbc1a5cc-bcc1-4a97-a7bd-62b06b7baeb4%2Fdwjs8jt_processed.png&w=3840&q=75)
Transcribed Image Text:**Interference Pattern Analysis Using a Helium-Neon Laser**
**Experimental Setup Description:**
Light from a helium-neon laser (\(\lambda = 633 \, \text{nm}\)) is utilized to illuminate two narrow slits. The resulting interference pattern is projected onto a screen positioned 2.8 meters behind the slits. The pattern displays twelve bright fringes stretching across a distance of 55 millimeters.
**Problem Statement (Part A):**
Determine the spacing (in millimeters) between the slits.
**Instructions:**
Provide your answer using two significant figures.
**Solution:**
The spacing between the slits is calculated as follows:
\[ d = 0.0805 \, \text{mm} \]
This solution assumes a baseline understanding of interference patterns and the application of relevant physics equations to solve for slit spacing. For educational purposes, the method to solve for \(d\) involves the use of the fringe spacing formula:
\[ d = \frac{m\lambda L}{x} \]
Where:
- \(d\) is the spacing between the slits
- \(\lambda\) is the wavelength of the light
- \(L\) is the distance from the slits to the screen
- \(x\) is the distance over which the fringes are observed
- \(m\) is the number of fringes
This exercise provides a practical application of theoretical physics concepts in the field of optics.
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