(i) Prove that sec 3x(sin 3x-2sin' 3x)= tan 3xcos 6x. (ii) Hence find, for 0s.xs, the values of x in radians for whicl- 3 3 -2 sinxcosx= sec 3x(sin3x--2 sin' 3x). 3
(i) Prove that sec 3x(sin 3x-2sin' 3x)= tan 3xcos 6x. (ii) Hence find, for 0s.xs, the values of x in radians for whicl- 3 3 -2 sinxcosx= sec 3x(sin3x--2 sin' 3x). 3
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
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
Transcribed Image Text:(i) Prove that sec3x(sin 3x-2sin' 3x)= tan 3xcos 6x.
(ii) Hence find, for 0sxs, the values of x in radians for which
3
3
-2 sinx cosx= sec3x(sin3x-2sin'3x).
2
2
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