i need to know how they got the value of 52.89 from the eqaution
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I need help rearranging a formula. question 11 shows the question i am working on , the other is an example that has been done. i need to know how they got the value of 52.89 from the eqaution. i need to rearrange to find the stress
![b) Here we need to use the definition of K:
K, = Yo (ra)
le
With Y = 1.12, a = 0.1mm and K1c = 1.05 MPa.m0.5, gives o = 52.89 MPa](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F86cb1182-9e3b-4dd2-a1fe-92383e28551c%2F177c32b9-4368-45a2-ba49-a9c38b03ebbe%2Fjm55pmn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:b) Here we need to use the definition of K:
K, = Yo (ra)
le
With Y = 1.12, a = 0.1mm and K1c = 1.05 MPa.m0.5, gives o = 52.89 MPa
![For a particular polymer, the value of K1c is 1.5 MPa.m1/2
For this material, a continuous pipe has a diameter of 1.3 m and a wall
thickness of 29 mm. It has a small crack on the outside of the pipe, running
in the direction of the pipe and this crack is 0.8 mm deep.
What internal pipe pressure would cause this crack to grow rapidly and
cause failure of this pipe?
For this geometry, assume the value of Y is 1.12.
Submit your answers in kPa, as an integer, but without the units. You have
a 2% error margin for this.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F86cb1182-9e3b-4dd2-a1fe-92383e28551c%2F177c32b9-4368-45a2-ba49-a9c38b03ebbe%2F4gq7c4s_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For a particular polymer, the value of K1c is 1.5 MPa.m1/2
For this material, a continuous pipe has a diameter of 1.3 m and a wall
thickness of 29 mm. It has a small crack on the outside of the pipe, running
in the direction of the pipe and this crack is 0.8 mm deep.
What internal pipe pressure would cause this crack to grow rapidly and
cause failure of this pipe?
For this geometry, assume the value of Y is 1.12.
Submit your answers in kPa, as an integer, but without the units. You have
a 2% error margin for this.
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