I need help with problem 5 because the Current answer I got is I = e-40t( 2cos(30t) + (242/3)sin(30t) ) Which is different from the answer shown below
I need help with problem 5 because the Current answer I got is I = e-40t( 2cos(30t) + (242/3)sin(30t) ) Which is different from the answer shown below
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.5: Product-to-sum And Sum-to-product Formulas
Problem 2E
Related questions
Question
Linear Second-Order Equations
I need help with problem 5
because the Current answer I got is
I = e-40t( 2cos(30t) + (242/3)sin(30t) )
Which is different from the answer shown below
Transcribed Image Text:6.3.5 (p. 295) I = -e-40t (2 cos 30t - 86 sin 30t)
Transcribed Image Text:6.3 Exercises
In Exercises 1-5 find the current in the RLC circuit, assuming that E (t) = 0 for t > 0.
1. R = 3 ohms; L = .1 henrys; C = .01 farads; 2o = 0 coulombs; Io = 2 amperes.
L = .05 henrys; C = .01 farads'; Qo = 2 coulombs; Io = -2 amperes.
2.
3.
L = .1 henrys; C = .01 farads; 20
=
2 coulombs; Io = 0 amperes.
4.
L = .1 henrys; C = .004 farads'; Qo
5.
L = .05 henrys; C = .008 farads; Qo = -1 coulombs; Io = 2 amperes.
R = 2 ohms;
R = 2 ohms;
R = 6 ohms;
R = 4 ohms;
= 3 coulombs; Io = -10 amperes.
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