Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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I need help with Graph 2x = −2y + 16 by finding the intercepts.
Transcribed Image Text:Graph 3x = -5y + 8 by finding the intercepts.
We will let x = 0 to find the y-intercept of the graph. We will then let y = 0 to find
the x-intercept.
Since two points determine a line, the y-intercept and x-intercept are enough
information to graph this linear equation.
We find the intercepts and select x = 1 to find a check point.
y-intercept: x = 0
x-intercept: y = 0
Check point: x = 1
Зх %3D — 5у + 8
3x = -5( 0V ) + 8
= -5y + 8
) = -5y + 8
3x = -5y + 8
3x =
) = -5y + 8
0 = -5y + 8
3( 0
3( 1
3
X = 8
3 = -5y + 8
-8 V = -5y
8
X =
-5
= -5y
-8 X =y
3
1 V = y
A check point is (1, 1).
2
X = 2
1
= y
x-intercept is (24, o).
The
The y-intercept is (0, 12).
The ordered pairs are plotted as shown, and a straight line is then drawn through them.
y
3x = -5y + 8
3.
2.
Зх %3D — 5у + 8
(1, 1)
(0.)
(3.0)
0, 1
X
y
(х, у)
8
4
-2
1
4
= (0, 12) - y-intercept
(2를,이)
8
e x-intercept
-3
1
1
(1, 1)
e Check point
II
Transcribed Image Text:4
Graph 2x =
-2y + 16 by finding the intercepts.
10
Graph Layers
Clear All
9.
Line 1
7
Delete
Point 1
4
Fill
-10 -9
-8
-7
-5
-2
2
3
5
6.
8.
6.
10
-1
-2
No
-3
Solution
-4
-5
-6
-7
-8
-9
-10
Help
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